Consider sinc(x):where sinc(x)=sin (xpi)/xpi. and sinc(x) have max value i.e. unity at x=0 .now if x=0.then pix =0 and sin (pix)=0 at x=0. then above expression sin (xpi)/xpi.should be of 0/0 form i.e. in-determined form. then how sinc(x) is one at x=0. pi is constant.

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i want to know the rrb section engg. the question paper also with interview questions.pls mail me at shekharmunna130@gmail.com

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