11/.433KV, 100KVA TRANSFORMER is supplied with .433KV AT
ITS PRIMARY. HOW MUCH KVA IT CAN SUPPLY
Answers were Sorted based on User's Feedback
Answer / vikramvijayk
The answer is 100KVA(losses are negiable) because In an
transformer the KVA must be same to both side(PY&SY).
|Is This Answer Correct ?||10 Yes||5 No|
Answer / vikas
As the xmer is havin its rating in kva so it depends only on voltage and current so if voltage increases thn current decreases and vice versa so if primary voltage is increased so its current decreases nd vice versa. So if secondary voltage is 11kv thn current in secondary will increase so i think kva will remain same.
|Is This Answer Correct ?||3 Yes||0 No|
The full load secondary current of 11/0.433 kV, 100 kVA
trafo is 140 Amps. This much current only can flow on the
secondary. The secondary voltage when 433 V is fed to the
primary is 17 Volts (433x433/1000). Hence it would give
about 4 kVA. (1.732x17x140/1000)
|Is This Answer Correct ?||4 Yes||2 No|
Answer / nagaachi
IT S ME WHO THE QUESTIAN IS ASKED,
MY IDEA IS THAT,
IF IT HOLD GOOD THE RELATION 5.2(root3*voltage)
thus we can get the answer as 5.2(root3*.433)=3.89KVA
PLEASE HELP ME GETTING THE SOLUTION
THIS QUESTIAN TEASING ME
|Is This Answer Correct ?||5 Yes||6 No|
Answer / s.arul
transformer only changed the voltage & current
rating. so not changed the KVA.
KVA = KV * A
SO, PRIMARY SIDE
100 = 11 * A
A = 100/11 SO CURRENT = 9.09 AMPS
100 = .433* A
A = 100/.433 SO CURRENT = 230.95 AMPS
|Is This Answer Correct ?||3 Yes||7 No|
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