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in step1 of a jcl,disp=(mod,delete,delete)
step02 exec pgm=ccc,cond=(0,le)
will step02 be executed?
i)never
ii)always
iii)
iv)...
i dont remember options
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Answer / y@$w@nth
disp=(mod,delete,delete)
will tells that if the file is not previously created create
it if it is already created then use that file.
the two delete statements will tell that delete the file
after norml and abnormal termination.
step02 exec pgm=ccc,cond=(0,le)
Here step02 was coded as condition code which always falls
to true so this step wont execute in any situation......
| Is This Answer Correct ? | 26 Yes | 0 No |
Answer / vinay sonar
Step2 will not execute because always true condition is
coded in step2.
condition code(cc) 0 will be always less than any previous
step cc say 0,4,8,4095 etc. so condition is always true.So
step2 wont execute
| Is This Answer Correct ? | 3 Yes | 0 No |
Answer / sowmya
step2 will be executed.the steps after the step2 will be by-
passed
| Is This Answer Correct ? | 1 Yes | 9 No |
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