Answer / kedar malusare

The de Broglie equations relate the wavelength (lamda) and
frequency (f) to momentum (p) and energy (E) respectively.

lamda = h/p

f = E/h

Where h = plank's constant

(personally I never came read about it in my curriculum)

Answer / deep

E=mc2
K.E=V.e=1/2 mv2

lamda=h/mc ,here c is velocity of light . for electron of
mass m and velocity v .

lamda=h/p ,p is momentum

Answer / parth

wavelength,
lambda=h/mv
where,
h = plank's constant
m=mass of particle(photon/electron)
v=velocity.

Please tell about the water type h.v.a.c with it's cycle and functions of each parts ?show me how talented u r?

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