What is the relationship between the universal
gravitational constant (G) and the acceleration due to
gravity (g)?
Answers were Sorted based on User's Feedback
Answer / gagandeep garg
F = G x M x m/ r2
E = F x r = (G x M x m/ r2) x r
E = mgr = (G x M x m/ r2) x r
=> g = G x M/ r2
OR G = g{r2/M}
where,
F = Force of attraction between twoo bodies(N/m2)
E = energy in smaller body w.r.t the heaviour body(J)
M = mass of heaviour body/planet (kg or slug)
m = mass of smaller body(kg or slug)
g = acceleration due to gravity (m/s2 or ft/s2)
G = universal gravitational constant (m3/kg/s2 or
ft3/slug/s2)
r = distance between the centres of the two bodies(m or ft)
The value of G is known and has been estimated by
scientists as:
G = 6.673 x 10-11 m3/kg/s2 in the Metric system
G = 3.439 x 10-8 ft3/slug/s2 in the English system
Is This Answer Correct ? | 69 Yes | 39 No |
Answer / niharika
we know that
F=GMm/r2
mg=GMm/r2 (F=mg)
g=GM/r2 (cancel'm')
Is This Answer Correct ? | 46 Yes | 17 No |
Answer / guest
The value of G is a constant that should not change no
matter where one is in the universe. The value of g,
however, does vary for each planet, star, moon, or other
large body. These two gravitational parameters are related
by the equation:
where
g = acceleration due to gravity (m/s2 or ft/s2)
G = universal gravitational constant (m3/kg/s2 or
ft3/slug/s2)
M = mass of the body (kg or slug)
r = radius of the body (m or ft)
The value of G is known and has been estimated by
scientists as:
G = 6.673 x 10-11 m3/kg/s2 in the Metric system
G = 3.439 x 10-8 ft3/slug/s2 in the English system
Is This Answer Correct ? | 44 Yes | 35 No |
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