sir, plz tell me how much kvar capacitor required for 1000
amp or 500 Kw load ? what is the formula ?




Answers were Sorted based on User's Feedback



Answer / madhu253

Formula : KVAR = KW(tanĂ˜1-tanĂ˜2)

Is This Answer Correct ?    35 Yes 10 No

Answer / prakash veer singh

Dear Shovan
This is Prakash veer
According to madhu's formulas,

KVAR= KW* (tanQ1-tanQ2)

Q1 is intail power factor
Q2 is target power factor

Is This Answer Correct ?    19 Yes 4 No

Answer / arun

we need power factor value

Is This Answer Correct ?    14 Yes 4 No




Answer / santosh maske

Required data for calculation your demand KVAR

1.Existing P.F of Load (tanQ1)(0.92)
2.Required P.F (Improvement in P.F)-(tanQ2)(0.99)
3.Supply Voltage - for reference(Voltage variation if any)
4.Load in KW (exam- availabl with you i.e 500KW)

KVAR= KW(tanQ1-tanQ2)
KVAR= 500(tan0.92- tan0.99)
KVAR = 500(0.2890)
KVAR = 141.75 KVAR (@ 142KVAR)
if you want to calculate by amp need following data
efficiency of motor, required P.F, KW,maganatising current
of motor,formula find in Electrical Machine Engineering

Is This Answer Correct ?    9 Yes 2 No

Answer / deepak

kVAR=kVA X sinphi
SO, sin phi=(1-cos sq phi) underroot.
SO POWER FACTOR IS REQUIRED.

Is This Answer Correct ?    7 Yes 3 No

Answer / shovan

Madhu pls explain what is tanphi1 and tanphi2????

Is This Answer Correct ?    5 Yes 1 No

Answer / elangkumanan

25 kvar = 32amps load taken
12.5 kvar =16amps load taken
l6.25 kvar =8amps load taken
3.125kvar =4amps load taken
1.0775kvar =2amps load taken


1000amps capacitor required to 500kvar

Is This Answer Correct ?    5 Yes 1 No

Answer / malkit singh

250 Kvar Capacitor bank is required for 500Kw load
(i.e,625Kva).
This is because the capacitor rating for any load is equal
to 40% of Kva.
i.e, Capacitor required=40%x Kva Load

Is This Answer Correct ?    7 Yes 5 No

Answer / saleem iqbal

plz identify your systems existing power factor and
targeted power factor which u want to improve, then apply
this formula
KW X (Tan phi 1 - tan phi 2)

Is This Answer Correct ?    2 Yes 0 No

Answer / bijoy roy

Reactive power (KVAR) is increase due to run inductive load.as a result power factor is lagging. so have to use capacitive power to reduce this inductive or reactive load. generally we have to use 63% capacitive load to remove the reactive load.i.e.

active power=500KW
so 60% of this will be=(60*500/100) = 300 KVAR

so we have to use 300KVAr capacitive capacitor bank to remove this reactive power .

Is This Answer Correct ?    1 Yes 0 No

Post New Answer



More Electrical Engineering Interview Questions

How to calculate the Harmonics losses in terms of cost/unit.

0 Answers  


when a machine act as genartor and as motor?

2 Answers  


BRIEF ME CHECKING PRCEDURE OF BATTERY 12V 26AH

1 Answers   DRJ ARDE,


I WANT BHEL PREVIOUS QUESTION

0 Answers   Bhel,


how to design coil turns ?

0 Answers   L&T,


Dear,  How much ph is maintained of water electrolite used in lrs for slipring induction motor ?

1 Answers  


What is the formulae of Megger value for a A.C.Motor

0 Answers  


what is called star connection and delta connection also purpose of this connections?

3 Answers   Siemens,


why we do not switched on capicitor panel with DG Supply

3 Answers   DLF,


what is the difference between control transformer and Potential transformer (PT)?

1 Answers  


Sir Power transformer :- (in generating station) Alternator terminals side - Delta HT transmission line side - Star Why?

4 Answers   Kirloskar,


list down a few application of ac & dc in a generating station?

1 Answers  




Categories
  • Civil Engineering (4460)
  • Mechanical Engineering (3652)
  • Electrical Engineering (15440)
  • Electronics Communications (2613)
  • Chemical Engineering (612)
  • Aeronautical Engineering (78)
  • Bio Engineering (30)
  • Metallurgy (95)
  • Industrial Engineering (190)
  • Instrumentation (2831)
  • Automobile Engineering (134)
  • Mechatronics Engineering (40)
  • Marine Engineering (59)
  • Power Plant Engineering (157)
  • Engineering AllOther (1316)