how we can calculate which capacity capacitor bank we have
to add for improve pf?
Answers were Sorted based on User's Feedback
Answer / abdulsubur
p total connect load in kw =932
cos 1 =power factor before improvement =0.8 assume
cos 2= poer factor after improvement =0.9
kvar 1= ptan1 932*0.75=699.03kvar
kvar 2=ptan2 932*.4843=451.39kvar
req rating of capacitor bank =kvar1-kvar2
=699.03-451.39
=247.64kvar =250kvar
Is This Answer Correct ? | 12 Yes | 4 No |
Answer / z_hosen
More simply,
Let total power is 1500kw
assume
cos 1 =power factor before improvement =0.75
cos 2= poer factor after improvement =0.98
tan1=0.88
tan2=0.2
and
kvar 1= power*tan1=1500*0.88=1320kvar
kvar 2=power*tan2=1500*0.2=300kvar
now, required rating of capacitor bank =kvar1-kvar2
=1320-300
=1020kvar =1000kvar
thanking u
z_hosen@yahoo.com
Is This Answer Correct ? | 11 Yes | 4 No |
Answer / karuppiah
Let total power is 1500kw
assume
cos Q1 =power factor before improvement =0.75
cos Q2= poer factor after improvement =0.98
tan1=0.88{cos Q1=0.75,Cos-0.75=46.01degree,Now angle is
46.01,so tan(46.01)=0.88}
tan2=0.2
and
kvar 1= power*tan1=1500*0.88=1320kvar
kvar 2=power*tan2=1500*0.2=300kvar
now, required rating of capacitor bank =kvar1-kvar2
=1320-300
=1020kvar
Capacitor Bank should connect parallel with the load.
Thanks
Karups
Is This Answer Correct ? | 2 Yes | 1 No |
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