Hai I have 2500KVA,Transformer,13.8KV/380.DELTA/STAR.How
much load that I can take interms of current?How can I
calculate also when I have loads in KW?
Answers were Sorted based on User's Feedback
Answer / shalini.b
Transformer Ratio is given by
k=(v1/v2)=(N1/N2)=(i2/i1)
where
V1 : voltage at the primary side
V2 : Voltage at secondary side
like wise for current(i)& Number of turns(N)
k= V1 /V2
= 13800/380
=36.31
P=1.73*V*i*cos(phi)
input power
p1=1.73*v1*i1*cos(phi)
i1=(2500*0.8)/ (1.73*13.8*0.8)
= 104 Amps
k = i2 /i1
So i2 = 104*36.31
=3776
Is This Answer Correct ? | 15 Yes | 6 No |
Answer / k.murugesan - tamil nadu
In Delta Connection
Line Voltage VL = Phase Voltage VP But Line Current IL =
1.73205 times of Phase Current IP.
In Star Connection
Line Voltage VL = 1.73205 times of Phase Voltage VP But Line
Current IL = Phase Current IP.
Is This Answer Correct ? | 4 Yes | 1 No |
Answer / harpreet
primary current- 104.61A
secondry current- 3798.52A
KW- 2000
Is This Answer Correct ? | 2 Yes | 1 No |
Answer / k.murugesan
Hi I am K.Murugesan BE EEE working at Tidel Park Ltd Chennai
as a O&M Manager.
KVA=1.732*V*I
KW=1.732*V*I*Cos.Phi
Primary Current=KVA/(1.732*13.8KV)
Primary Current= 2500/(1.732*13.8)
= 104.592A(HT.Amps)
Load Current/Secondary Current = 2500/(1.732*380)
Load Current/Secondary Current = 3.798357 KA
= 3798.357A (LT Amps)
You can Load up to 80% of Loads with safe operation.
Transformer does not consider PF.
It is only on Load side have to be maintain 0.8Lag to Unity.
Regards
K.Murugesan.
9789048244
Is This Answer Correct ? | 2 Yes | 2 No |
Answer / musaad al-mutairi
hello ,
i want to ask about the connection because no body talked
about the role of delt/star connection
do you have any useful point
thanks all
Is This Answer Correct ? | 1 Yes | 2 No |
Answer / tapan
Total power in kw =2000 kw
primary current of trafo is
181 amp (roundfigure)
secondary current is 6578
amp
Is This Answer Correct ? | 0 Yes | 1 No |
Answer / saqib haroon
as per my point of view,answer of the input current is
wrong. Why the respectable brother put power factore value
with KVA rating, as per formula only once we will put PF
value, which will divide this KVA rating.
In this case the answer will be
P1= 1.73*V1*I1*cosphi
2500= 1.73*13.8*I1*0.8
2500/1.73*13.8*0.8= I1
131 A = I1
Remaining portion is OK
Is This Answer Correct ? | 3 Yes | 5 No |
Answer / sanjay kolambekar
3798 A at unity power faactor and it can very linerly with
change in P.F
Is This Answer Correct ? | 0 Yes | 3 No |
Answer / satheesh kumar
Primary Current is 181.15 Amps.
Secondary Current is 6578.65 Amps.
Power is 3463.8 KW
Is This Answer Correct ? | 4 Yes | 13 No |
Are Karani,
I think you are not electrical engineer, it is a basic
thing,
You just calculate through following formulas :
KW= 1.732 * V * I * Cosphi
KVA=1.732 * V * I
So, I= 1.732*1000/(V * I)
Is This Answer Correct ? | 1 Yes | 15 No |
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