Answer Posted / k.murugesan

Hi I am K.Murugesan BE EEE working at Tidel Park Ltd Chennai
as a O&M Manager.
KVA=1.732*V*I
KW=1.732*V*I*Cos.Phi

Primary Current=KVA/(1.732*13.8KV)
Primary Current= 2500/(1.732*13.8)
= 104.592A(HT.Amps)

Load Current/Secondary Current = 2500/(1.732*380)
Load Current/Secondary Current = 3.798357 KA
= 3798.357A (LT Amps)
You can Load up to 80% of Loads with safe operation.

Transformer does not consider PF.
It is only on Load side have to be maintain 0.8Lag to Unity.

Regards
K.Murugesan.
9789048244

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