Answer / narasimham

If the rated current of the CT is 2600/5 amps, then the
secondary voltage will be (420000x2600)/5= 218400000
(i.e.218400kv)

Answer / narasimham

Correction to answer: If the secondary is open voltage will
be 218400 kv and it will be '0', if it is shortcircuited

Answer / sathiyaseelan.m

I dont thing 420kV CT available. If it available CT
secondary voltage is proposnal to Burdon. Ex if a meter
takes 10VA if CT sec. 5A than Voltage will be 2V

Answer / ramniveth

There is no Current Transformer 420kV

Answer / ashish patil

secondary voltage is 0. Bcz it is current transformer which
has short circited secondary. O/p is 1A.

Answer / panchanna

1A

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