For testing 33kv cable hipot testing. How much kv we have to
Apply .Give in details.
Answers were Sorted based on User's Feedback
Answer / zahid ali
2E + 1 KV = 67 KV DC Hi pot
67 * .707 = 47 KV AC Hi pot
Is This Answer Correct ? | 119 Yes | 57 No |
Answer / bapi
AS HI POT TEST IS CONDUCTED IN DC SO APPROX. 1.5 TIMES OF
AC SUPPLY VOLTAGE IS APPLIED FOR 1 MINUTE.
FOR 33 kV CABLE APPROX. 50kV FOR 1 MINUTE WILL BE APPLIED.
FOR TESTING OF "R" PHASE WE HAVE TO SHORT "Y" AND "B" PHASE
ALONG WITH ARMOUR & IT SHOULD BE EARTHED. SIMILARLY FOR Y &
B PHASE.
AFTER EACH PHASE TESTING IT SHOULD BE DISCHARGED THROUGH
DISCHARGE RODS.
Is This Answer Correct ? | 65 Yes | 30 No |
Answer / s.jeganath
(2E+1)1.414=dc
2E+1 =AC
(2*33000+1)1.414=DC
67000*1.414=DC
94738v=DC (it is a 100%)
but apply in 80% only it is standard for 33kv cable
APPly voltage dc=94738*0.8=75790V
(75.790KV DC)
Is This Answer Correct ? | 42 Yes | 18 No |
Answer / mathiraja
2E+1KV=67KV FOR AC VOLTS
(2E+1KV)*1.414=94.73KV FOR DC VOLTS
ACCORDING TO IEC60950 STANDARDS.
Is This Answer Correct ? | 21 Yes | 2 No |
Answer / manikandan n
For DC Hipot test the applied voltage calculating formula is equal to (2E+1000)*1.414*(80/100)
E = system voltage
1.414 = For DC RMS conversion.
80% = test conduct in site at second time.
Is This Answer Correct ? | 17 Yes | 4 No |
Answer / ram sundar
For DC HIPOT = 1.414*(2E+1)
E=33/1.73=19.07
DC Hipot = 1.414*(2*19.07+1)
55.34kv approx 56Kv
Is This Answer Correct ? | 8 Yes | 0 No |
Answer / sunil choudhary
FOR TESTING 6.6KV CABLE HIPOT TESTING.HOW MUCH KV WE HAVE
TO
APPLY .GIVE IN DETAILS.
sunil choudhary
Is This Answer Correct ? | 20 Yes | 15 No |
Answer / yousaf
D.C. voltage equal to 3 x U0 shall be applied for 15 minutes. The standard is 1EC5840.
57KV FOR 15 MIN.
Is This Answer Correct ? | 9 Yes | 5 No |
Answer / jim sreedharan
For 33 KV cables we do three tests.
1. Vlf Test: We apply 10 kv dc between graphite and armour
at a low frequency (normally between 0.02 hz to 0.05 hz)
for 1 hour.
2. Insulation Resistance :- We apply 5 kv dc for 1 min
3. High Voltage ac Test:- We apply 57.1 kv for 30 mins
(33/1.732)x 3 = 57.1 kv
God Bless
Is This Answer Correct ? | 12 Yes | 9 No |
Answer / jayasanker
33KV CABLE
FORMULA:2E+1*1.414
2*33+1*1.414 = 94KV DC
IF BUS BAR 2*33+1 = 67KV AC
Is This Answer Correct ? | 8 Yes | 5 No |
why using transformer and thyristor switch in 3 phase apfc panel
what is the function of 1 phase preventer?
Is single load(eg: three phase motor) having all the components like positive,negative,zero sequence components during fault condition?
how net resistance islow in star connection and viseversa in delta connection...? if anybody could explain in detail it wud be helpful.
what main difference betwenn invetter & ups & major difference
which safety we have to take when we go for work?
what perpose of use CT ratio in gt,st,uat
why motor range is available 22kv,30kv,37kv,45kv and so on? why motor range is not available 21kv,24,25,26,27kv and so on?
what is the formula for calculate the turns in Transformers
if we apply 1000ADC instead of 100ADC or We apply 50ADC instead of 100ADC,What will be happened in the test result value.Pl explain
TNC switch is also available in 1NO+1NC. What does it mean ?
Leading power factor means what? what is the power factor value while in power factor is leading? is power factor greater than one? In some cases i heard pf 0.8 leading then what about 0.8 lagging?
1 Answers Rockfort Engineering,