Answer / amr hamad

the transformer should not be full loaded all the time so,
its maximum load should be .8 of its full load rating =400kva
so , maximum power of motor should not increase 320kw with
0.8 pf

Answer / dinesh kannan

Since the motor is connected in 433V side , we consider
powerfactor 0.8.so maximum connected capacity of motor is
500*0.8, but we have to run the motor in single start
there are so many methods are there to start the motor like
DOL, star delta starters based on the starter and starting
current of motor we deside the maimun rating of motor( to
start the motor, minimum 70% of voltage is required

Answer / mohit.k.k

500x.8 = 400 kw

Answer / vijay krishna rao

considering DOL type of starter (so starting time will be
appx 6 times the rated current)and also considering starting
time of motor may affect the Xmer, then 500/6=83.33 MVA.

Motor rating (pf=0.8)=83.33*0.8=66.66kW (efficiency=100%)

If soft starter is used then motor rating can go upto Xmer
rating.

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