How can we calculate the fault level of the distribution
system knowing the percentage impedance of transformer &
subsequent equipments.
Answers were Sorted based on User's Feedback
Answer / mbao richie
simply means the bus rated at that fault level can
withstand the electrical pressure(voltage) for which it is
designated for that period of time
Is This Answer Correct ? | 0 Yes | 0 No |
Answer / srikanth
Dear friends,
in the above calculations people consider the % impedence
but they are not calculate the fault impedence to get MVA
of transformer.
Is This Answer Correct ? | 0 Yes | 1 No |
Answer / jigar shah
suppose transformer (11 KV/433) is of 1000 KVA & %
impedance is 4 .LT side Fault level can be calculated as
below :
KVA = 1.732 X V X I X Cos Phi - PF assumed : 0.95
LT Rated current (I) = (1000 * 1000)/(1.732*433*0.95)
= 1481 A
Fault current on LT side = FLC * 100/(% impedance)
= 1481 * 100/5
= 29.62 KA
Is This Answer Correct ? | 44 Yes | 54 No |
Answer / laxminarayan
suppose transformer (11 KV/433) is of 1000 KVA & %
impedance is 4 .LT side Fault level can be calculated as
below :
KVA = 1.732 X V X I X Cos Phi - PF assumed : 0.95
LT Rated current (I) = (1000 * 1000)/(1.732*433*0.95)
= 1481 A
Fault current on LT side = FLC * 100/(% impedance)
= 1481 * 100/5
= 29.62 KA
Is This Answer Correct ? | 14 Yes | 46 No |
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