Suppose there are two vessels. One of diameter = D and
other vessel dia = d. Suppose in vessel with dia D, water
is filled upto height H and vessel with dia d is empty. Now
both vessels are connected.Water will flow from D dia vesel
to small d dia vessel.Suppose after equilibrium height of
water in vessel with dia D is h. How much is h in terms of
D, d,H etc?
Answers were Sorted based on User's Feedback
Answer / jikku joseph
Total vol of the water is remain constant
since v r not adding or removing any water
and that is equal to (3.14/4)*D^2*H
This must be equal to the sum of new of new vol of water in
2 cylenders
ie (3.14/4)*D^2*H= (3.14/4)D^2*h+(3.14/4)d^2*h
by solving this v can get
h=(D^2*H)/(D^2+d^2)
Is This Answer Correct ? | 50 Yes | 3 No |
Answer / arun
@shivaray...i dont think there is any relation b/w d and
H..so choosing the new volume with (H-h) is wrong...the
volume in the vessel wit 'd' as dia shud have only h and
not H-h...so the final ans is
h=D^2*H/(d^2+D^2)..
Is This Answer Correct ? | 9 Yes | 0 No |
Answer / jodh
Hi Shivararay, Sorry to say that your answer is not exactly
right but your logic is very appereciating .........Height
after equablibrium in both the vessels will be equal
because of atmospheric pressure.So, height for dia. d is
not H-h.
I congratulate mr. Arun for his Correct answer i.e.
h= D2H/(D2 + d2)
Is This Answer Correct ? | 3 Yes | 1 No |
Answer / siddaraju v
volume (Pi*D^2/4)*H=volume {(Pi*d^2/4)*h+(Pi*D^2/4)*h}
i.e.
h=H/{1+(d/D)^2}
Is This Answer Correct ? | 2 Yes | 0 No |
Answer / akansha
Answer
# 2 is correct.
Don't consider other options..
Is This Answer Correct ? | 1 Yes | 0 No |
Answer / abhinav patel
vol before connecting = vol after equlibrium
(3.14/4)*(D^2)*H = (3.14/4)*(D^2)*h +(3.14/4)*(d^2)*H
(3.14/4)*(D^2)*H = (3.14/4)h{(D^2)+(d^2)}
h={(D^2)/(D^2)+(d^2)}* H
pls sent me its correct or not
Is This Answer Correct ? | 4 Yes | 4 No |
Answer / vishnu
@ jikku
ur answer is correct only if the two vessels are kept at
same level
Is This Answer Correct ? | 0 Yes | 0 No |
Answer / sudip
If their base level is equal,then ans is "h" for both of them
else,
the volume of water decrease in "H" dia vessel=the volume occupied by that water in "h" dia vessel.
therefore the correct ans is
height=D^2*(H-h)/d^2
Is This Answer Correct ? | 0 Yes | 0 No |
Answer / banke bihari
h=(D^2*H)/(D^2+d^2)
beacause after equlibrium is achieved, the height of water
in both the vessels must be same.
3.14h(D^2+d^2)/4=3.14D^2H/4..
Is This Answer Correct ? | 2 Yes | 3 No |
Answer / deepak waje
sum of volumes of the water in both vessel will be equal
to the volume of water in vessel with dia D & filled up to
height H.
so as per equation,
D(H-h)=dh
Is This Answer Correct ? | 0 Yes | 2 No |
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