Two methanol-water mixtures are contained in separate tanks. The first mixture

Two methanol-water mixtures are contained in separate tanks. The first mixture contains 40.0 wt % methanol and the second contains 70.0 wt % methanol. If 200 kg of the first mixture is combined with 150 kg of the second, what are the mass and composition of the product? The symbol of weight percent is wt %.

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Two methanol-water mixtures are contained in separate tanks. The first mixture contains 40.0 wt % m..

Answer / kang chuen tat

Total mass of product mixture = 200 kg + 150 kg = 350 kg. Total mass of methanol in product mixture = 0.4 x 200 + 0.7 x 150 = 80 kg + 105 kg = 185 kg. Mass fraction of methanol in product mixture = 185 / 350 = 0.5286 or 52.86 wt %. Mass fraction of water in product mixture = 1 - 0.5286 = 0.4714 or 47.14 wt %. The answer is given by Kang Chuen Tat; PO Box 6263, Dandenong, Victoria VIC 3175, Australia; SMS +61405421706; chuentat@hotmail.com; http://kangchuentat.wordpress.com.

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Two methanol-water mixtures are contained in separate tanks. The first mixture contains 40.0 wt % m..

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