Plastering with cm 1:5 mix( one cement and five sand )
to 12 mm thick. How much Bag of Cement (50 Kg) and Sand (Cum)
Answers were Sorted based on User's Feedback
Answer / p. jairaj
Plastering in cm 1:5
1 part - cement
5 part - sand
total - 1+5 = 6 part.
Thickness of plastering - 12mm
Volume of mortar required for 1sqm
vol of mortar = 1.0 x 1.0 x 0.012 = 0.012cum.
volume of dry mortar of 1cum of wet mortar = 1.57cum
vol of dry mortar = 1.57x0.012cum = 0.01884cum.
vol of cement = 0.01884 ( 1/6) = 0.00314cum
Qty of cement in kg = 0.00314cum x 1440kg/cum = 4.5216kg
qty of cement in bags = 4.5215/50 = 0.0904 bags
qty of sand = 0.01884cum ( 5/6)= 0.0157cum.
Is This Answer Correct ? | 11 Yes | 0 No |
Answer / bhupendra singh panwar
ratio-1:5 12mm thickness take 1 sqm
0.012 x 1= 0.012
30% increase by mortar for fill up joit uneven surface of wall
0.012 X 0.30 =0.0036+0.0012=0.0156
increase of 25% dry volume
0.0156 X 0.25=0.0039+0.0156=0.0195/1+5=0.00325
cement= .0975 beg
sand =0.0162 cum
Is This Answer Correct ? | 2 Yes | 0 No |
Answer / gyana prakash
taking 100 m2 wall plastering will be 2 cubic meter . hence
amount of sand = 2*5/6=1.67 m*3 and cement = 2/6=0.33 m*3 =9.5 bags
Is This Answer Correct ? | 6 Yes | 7 No |
Answer / pintu
How many area required??? If 1 sqm. Then 1*1*0.012= 0.012 cum 0.012/6 =0.002 , 0.002*30=0.06 paket. 0.06*50=3kg
Is This Answer Correct ? | 0 Yes | 4 No |
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