Answer / selvanathan

in 1:2:4 concrete:

Take try volume : 54%

So, add try volume for 1 cum - concrete = 1.54

Cement volume:

1.54/(1+2+4)= 0.22 cum.
convert to kg. 0.22x1440=316.80 kg
Convert to bags = 316.8 / 50= 6.4 bags

Sand Volume:

0.22x 2 =0.44 cum. (2 is ration of sand)

Aggregate volume:

0.22x 4 =0.88 cum. (4 is ratio of aggregate.)

Answer / krishna kumar.a

Example : concrete 1:2:4
Coarse aggregate =95% of volume =0.95 cum.
Fine aggregate = 50 % of coarse aggregate =0.475 cum.
Cement = 50 % of Fine aggregate =0.2375 cum.
=0.2375 * 1440 kg./ cum
=342 kg.

Answer / purushotham

simply multiply volume to its density

Answer / fahimabid

1) ADD 25% DRY VOLUME
2)SUPPOSE ITS 1:1.5:3 (M20) CONCRETE
3) CEMENT=(1.25/1+1.5+3)=.227 Bag
4)CALCULATE SAND & AGGREGATES BY RATIO

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