if my 6 kva UPS gives 20 min. backup at 100 % load, then at
25% load what is the backup time?
Answers were Sorted based on User's Feedback
Answer / miarcle
100% load means = 20 minutes so
25%load means 4x20minit=80 minits
| Is This Answer Correct ? | 10 Yes | 2 No |
Answer / gopalakrishnan
50 minutes
for example let us take four fans at 100% load for 20 minutes.
100% load means 4 fans = 20 minutes
75% load means 3 fans = 30 minutes
50% load means 2 fans = 40 minutes
25% load means 1 fan = 50 minutes
| Is This Answer Correct ? | 6 Yes | 1 No |
Answer / prakash kusuma
at 25% load a 6kva UPS give back up of 50 min
as at 100% = 20 min ok
50% = 40 min
25% = 50 min (40 min + 20 min = 60 min(no load)
- 10 min(25 % load )= 50 min( back up)
| Is This Answer Correct ? | 1 Yes | 0 No |
80min
100% load =20min
1% load=20*100 min
25% load=(20*100)/25min.
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / miracle
100% load means = 20 minutes so 25%x20minit=80 minits
| Is This Answer Correct ? | 3 Yes | 3 No |
Answer / jayesh
50 min
20min = 100% load
? = 25% load
=20*25/100
=50 min
| Is This Answer Correct ? | 2 Yes | 2 No |
Answer / s kumar
If 6 Kva UPS given 20 min. backup at 100%load
backup at (50%)100/2------20*2=40min
backup at (25%)100/4------20*4=80min
Then 80 min. Backup at 25 %load
| Is This Answer Correct ? | 0 Yes | 1 No |
How can we say that accuracy of measurement increases by using 3 or 4 wire RTD? because for example: If resistance of RTD element is say r ohms and Resistance of the cable from transmitter to RTD is R ohms And if 4 wire RTD is used, ____._____________________ R ohms | |_____._____________________ R ohms / \ / r ohms \ \ | |______.__________________ R Ohms | |_______._________________ R ohms Then the actual resistance measured will be: Total = r + R/2 + R/2 = r +R Ohms Note: r+R instead of r ohms. hence error
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