for 1cum how much bag of cement is used for M20 grade
Answers were Sorted based on User's Feedback
the ratio of M20 is1:1.5:3
so bag is requred to 7.96 bag
Is This Answer Correct ? | 37 Yes | 8 No |
Answer / raichand s.
M20 Grade is 1:1.5:3
Total quantity- 1cum
Total mix- 1+1.5+3=5.5
Apply Voids 54% i e
cement quantity={((1*1.54*)/5.5)=0.28CuM
so volume of 1 bag cement is 0.035CuM
Required bags=0.28/0.035 = 8 Bag cement
Is This Answer Correct ? | 15 Yes | 3 No |
Answer / pramod vs gowda
The mix proportion is 1:1.5:3
We find out the quantity of cement for 1cum
Dry co-efficient of cement is 1.52
Unit weight of cement 1440
Then
(1/(1+1.5+3))*1.52=0.276
0.276*1440=397.44kg/m3
1 bag cement is equal to 50 kgs
397.44/50=7.9488
So Approximately 8 bags of cement is for 1cum
Is This Answer Correct ? | 12 Yes | 1 No |
Answer / shaik mahammad sharif
For M 20 grade Concret 1:1.5:3 ratio is required
1 is Cement, 1.5 is Fine Aggregate and 3 is Coarse Aggregate
Add 50% of wet cement concret =1.55 Cubic M
Cement Require for Cub M =(1.55/(1+1.5+3))*30=8.45 Bags
Sand =0.281*1.5=0.42 Cub M
Meterial =0.281*3=0.84 Cub M
Is This Answer Correct ? | 5 Yes | 1 No |
Answer / raju sardar
As per the CPWD material consumption constants, 8.4 bags of
cement.
Is This Answer Correct ? | 3 Yes | 1 No |
Answer / deep dubey
it depends on mix . its design mix or nominak mix.
in nominal mix 8 bag and in designmix we use 270 to 320 kg.
Is This Answer Correct ? | 1 Yes | 0 No |
Answer / mohan kumar
ratio 1:1.5:3
total mixing =1+1.5+3=5.5
area 1 cu m
(1/5.5)1.56*1=0.284 cum
=0.284*1440
=408.94 kg/cum
=408.94/50
=8.17 bags
Is This Answer Correct ? | 0 Yes | 3 No |
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