Answer / jayaraaj.arumugam

mix design 1:2:4; (1+2+4 = 7)

(using 20mm aggregate)
Volume of ingredients - 1.57 ( thump rule)

Aggregate - 4/7 * 1.57 = 0.89 Say 0.9 m3

sand - 2/7 * 1.57 = 0.448 say 0.45 m3

cement - 1/7 * 1.57 = 0.224 say 0.225 m3

weight of cement required - 0.225 * 1440 = 324 kg.
if any mistake please inform...

Answer / pritesh .c . bhoi

mix desighn = 1:2:4= 7
quantity is 1 cum add 52% westage and shreankage
so 152 cum
cement = 1*1.52/(7)=0.21714 cum (dry volume)
volume of one bag is 0.0347 cum
so no of bags are 0.21714/0.0347= 6.25 nos say7 numbers
bags are required
sand = 2*1.52/(7)=0.43428 cum
course aggregates = 4*1.52/(7)=0.86857 cum so conclution
is
cement =7 nos bags
sand =0.43428 cum
course aggregates =0.86857 cum
if any mistake please informed . thank you

Answer / vikas patil

For 1 Cu.m Concrete (1:2:4)
Cement =1.52/(1+2+4)=.217 Cu.m=.217/.035=6.2 Bags
Sand=(1.52*2)/7=0.434 Cu.m
Agg.=(1.52*4)/7=.86 Cu.m
out of 0.86Cu.m of Agg use following Proportion of Agg.
20mm Agg=0.65*.86=.56 Cu.m(65%of 0.86Cum)
&
10mm Agg=0.35*.86=0.3 Cu.m(35%of 0.86Cu.m)

Summary=>
Cement=6.2 Bags,
Sand=0.434 Cu.m,
20mm Agg=0.56Cu.m,
10mm Agg.=0.30Cu.m

Answer / raaj

Dear sir,

aggregate is more quantity required then sand, then how it is possible?

sand use in per 1 cum=27.14cft
aggrigate use in per 1 cum=13.57cft
kindly clarify i also need the answer for unit wise.

Answer / er.puspak kumar sahu

concrete ratio=1:2:4
area=1cum
1+52%=1.52cum(add the extra 52% for dry material)
cement=1.52/(1+2+4)=0.217cum=(0.217/0.035)=6.2bags
(per bag cement volume=0.035cum)
sand=1.52/2=0.76cum=(0.76/0.028)=27.14cft
(0.028 is a conversion factor)
aggrigate=1.52/4=0.38cum=(0.38/0.028)=13.57cft
(0.028 is a conversion factor)
finaly=
cement use in per 1 cum=6.2bags
sand use in per 1 cum=27.14cft
aggrigate use in per 1 cum=13.57cft

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