how many cement use for 1cum concrete for 25Grade.
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Answer / kalyan
Dry Volume for 1 Cum Mix is 1.54 Cum.
Ratio for M25 is 1:1:2 = 1+1+2 = 4
1 Part of cement would be = 1.54/4 = 0.385 cum.
1 cum of cement = 30 bags of cement
0.385 cum of cement = 30 x 0.385 = 11.55 bags
1 bag of cement = 50 kg of cement
11.55 bags = 50 x 11.55 = 577.5 kg of cement
so the cement required is 577.5 kg for 1 cum of m25 grade.
Is This Answer Correct ? | 137 Yes | 62 No |
Answer / rajkumar
25 grade mix design is 1:1:2
total = 4
cement is 1 part =1/4 = 0.25 m3 of cement
1m3 of cement =1440 kg
0.25 m3= 360 kg
Is This Answer Correct ? | 179 Yes | 110 No |
Dry Volume for 1 Cum Mix is 1.54 Cum.
Ratio for M25 is 1:1:2 = 1+1+2 = 4
1 Part of cement would be = 1.54/4 = 0.385 cum.
1 bag of cement = .035 cum
total bag of cement = 0.385/.035 = 11 bags
1 bag of cement = 50 kg of cement
11 bags = 50 x 11 = 550 kg of cement
cement required for 1 cum of m25 grade concrete is 550 kg.
Is This Answer Correct ? | 81 Yes | 20 No |
Answer / ak
*M25*
Dry Volume for 1 Cum Mix is 1.54 Cum.
Ratio for M25 is 1:1:2 = 1+1+2 = 4
1 Part of cement would be = 1.54/4 = 0.385 cum.
1 bag of cement = .035 cum
total bag of cement = 0.385/.035 = 11 bags
1 bag of cement = 50 kg of cement
11 bags = 50 x 11 = 550 kg of cement
cement required for 1 cum of m25 grade concrete is 550 kg.
Is This Answer Correct ? | 13 Yes | 0 No |
Answer / yedidivgp
320 kg for Reinforced Concrete
280 kg for Plain Concrete as per IS 456.
Is This Answer Correct ? | 44 Yes | 41 No |
Answer / deivendran
M25 1:1:2
Cement 1/4 * 1.57 * 1440 = 565.2 kg/m^3
Sand 1/4 * 1.57 = 0.39/ CFT
20 mm metal. 2/4 * 1.57 = 0.785/ cft
Is This Answer Correct ? | 7 Yes | 4 No |
Answer / sumeet vinayak
M 25 is design mix concret & raito- 1/1/2
means 1 fourth bag cement uses & normaly one fourth
means .25 m3 & 1m3 cement-1440kg & 1440 ka 1/4
1440/4 ....360kg
Is This Answer Correct ? | 18 Yes | 16 No |
Answer / vidyasagar daley
from m10 to m20 are consider as nominal mix but m25 is
design mix .the ratio is also may consider as 1:1:2
calculation:
for 1cum concrete required fine,coarse aggregates are
0.46cum-fine aggregate and coarse aggregate is 0.92cum.
1(cement)/1(sand)x0.46x1440(cement
wt.kg/cum)=662kgs.or13.248bag.
(or)
25 grade mix design is 1:1:2
total = 4
cement is 1 part =1/4 = 0.25 m3 of cement
1m3 of cement =1440 kg
0.25 m3= 360 kg
Is This Answer Correct ? | 20 Yes | 19 No |
Answer / amirthaganesan.m
M25 mix has a ratio of 1 cement to 1 sand and 2 stone jelly.i.e 1:1:2. This means cement volume is half of stone jelly volume.To prepare 1cu.m of concrete we need 0.0 cu.m of jelly. So we need 0.9/2= 0.45 cu.m of sand. So weight of cement required = 0.45x1440 =648 kg of cement.approximately 13 bags.
Is This Answer Correct ? | 10 Yes | 10 No |
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