Answer / sandy

It is good to refer Kerns handbook of HE design. As all
knows HE has several functions like cooler, heater,
eveporator, condenser etc. So based on each kind of usage
the design procedure changes.
But one can say the basic eqaution for all types of HE
design is Q = U A Dt.

For more details refer Kern's handbook.

Answer / shekhar

This answer is correct

Answer / prathmesh gujarati

First of all find out the Heat Duty for both service as well
as process fluid. The next step is to find our Lmtd. And
finally find out the Over all heat Transfer Co-efficient and
than Heat Transfer Rate.

A concentric, counter-current heat exchanger is used to cool lubricating oil. Water is used as the coolant. The mass flow rate of oil into the heat exchanger is 0.1 kg / s = FO. For oil, the inlet temperature TIO = 100 degree Celsius and the outlet temperature TOO = 55 degree Celsius. For water, the inlet temperature TIW = 35 degree Celsius and the outlet temperature TOW = 42 degree Celsius. What is the mass flow rate of water in kg / s, FW needed to maintain these operating conditions? Constant for heat capacity of oil is CO = 2131 J /(kg K) and for water is CW = 4178 J /(kg K). Use the equation (FO)(CO)(TIO – TOO) = (FW)(CW)(TOW – TIW).

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