void main()
{
char a[]="12345\0";
int i=strlen(a);
printf("here in 3 %d\n",++i);
}
Answers were Sorted based on User's Feedback
Answer / susie
Answer :
here in 3 6
Explanation:
The char array 'a' will hold the initialized string, whose
length will be counted from 0 till the null character. Hence
the 'I' will hold the value equal to 5, after the
pre-increment in the printf statement, the 6 will be printed.
Is This Answer Correct ? | 18 Yes | 4 No |
Answer / ravneet kaur
as this is a character array and would have string in double
quotes so this code shows an error i.e. *char wont changes
to *int.
Is This Answer Correct ? | 0 Yes | 5 No |
1. const char *a; 2. char* const a; 3. char const *a; -Differentiate the above declarations.
I need your help, i need a Turbo C code for this problem.. hope u'll help me guys.? Your program will have a 3x3 array. The user will input the sum of each row and each column. Then the user will input 3 values and store them anywhere, or any location or index, temporarily in the array. Your program will supply the remaining six (6) values and determine the exact location of each value in the array. Example: Input: Sum of row 1: 6 Sum of row 2: 15 Sum of row 3: 24 Sum of column 1: 12 Sum of column 2: 15 Sum of column 3: 18 Value 1: 3 Value 2: 5 Value 3: 6 Output: Sum of Row 1 2 3 6 4 5 6 15 7 8 9 24 Sum of Column 12 15 18 Note: Your program will not necessary sort the walues in the array Thanks..
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