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void main()

{

char a[]="12345\0";

int i=strlen(a);

printf("here in 3 %d\n",++i);

}

Answer Posted / ravneet kaur

as this is a character array and would have string in double
quotes so this code shows an error i.e. *char wont changes
to *int.

Is This Answer Correct ?    0 Yes 5 No



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