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char s[]={'a','b','c','\n','c','\0'};

char *p,*str,*str1;




printf("%d",++*p + ++*str1-32);


#include<stdio.h> main() { char s[]={'a','b','c&..

Answer / susie

Answer :



p is pointing to character '\n'. str1 is pointing to
character 'a' ++*p. "p is pointing to '\n' and that is
incremented by one." the ASCII value of '\n' is 10, which is
then incremented to 11. The value of ++*p is 11. ++*str1,
str1 is pointing to 'a' that is incremented by 1 and it
becomes 'b'. ASCII value of 'b' is 98.

Now performing (11 + 98 – 32), we get 77("M");

So we get the output 77 :: "M" (Ascii is 77).

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