#define f(g,g2) g##g2
main()
{
int var12=100;
printf("%d",f(var,12));
}
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Answer / arnab maji
Hey Susie,
The ## is a concatenation operator,
When you pass the two arguments they get concatenated as
i/p --> f(g,g2) g##g2
o/p --> gg2
hence
f(var,12) will give us var12
effectively the printf statement gets modified as
printf("%d",f(var,12)); --> printf("%d",var12);
hence the output is 100 ie the value of var12.
| Is This Answer Correct ? | 56 Yes | 3 No |
Answer / vignesh1988i
the answer is 10012, the printf statement must be :
printf("%d",f(var12,12));
the number 12 will be concatenated by 100.
thank u.
| Is This Answer Correct ? | 7 Yes | 17 No |
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