Answer / rajendra kumar

#include<stdio.h>
#include<conio.h>
#define n 4
void main()
{
int A[n][n]={{1,2,3,4},{5,6,7,8},{9,10,11,12},{13,14,15,16}};
int min=0,max=n-1,i,j;
clrscr();
while(min<max)
{
for(i=min;i<=max;i++)
printf("%d,",A[min][i]);
for(i=min+1;i<=max;i++)
printf("%d,",A[i][max]);
for(i=max-1;i>=min;i--)
printf("%d,",A[max][i]);
for(i=max-1;i>min;i--)
printf("%d,",A[i][min]);
min++;
max--;
}
getch();
}

Answer / mahfooz

#include<stdio.h>
#define n 3
int main()
{
int arr[n][n]={{1,2,3},{4,5,6,},{7,8,9}};
int min=0,max=n-1,i;
while(min<=max)
{
for(i=min;i<=max;i++)
printf("%d ",arr[min][i]);
for(i=min+1;i<=max;i++)
printf("%d ",arr[i][max]);
for(i=max-1;i>=min;i--)
printf("%d ",arr[max][i]);
for(i=max-1;i>min;i--)
printf("%d ",arr[i][min]);
min++;
max--;
}
if(min==max) //this for odd case as n=3,5 etc
printf("%d \n",arr[min][min]);
return 0;
}

Answer / raghuram.a

#include<iostream.h>
#include<conio.h>
#include<stdio.h>
main()
{
int n,m,i=0,j=0,k=0,l=0,p=0,q=1,r=0,s=1,a=40,b=25,ar[100];
clrscr();
cout<<"enter n:";
cin>>n;
printf("enter array elements:");
for(m=0;m<n;m++)
scanf("%d",&ar[m]);
gotoxy(a,b);
m=0;
printf("%d",ar[m++]);
while(m<n)
{
while(i<=j)
{
i++;
a+=4;
gotoxy(a,b);
printf("%d",ar[m++]);
if(m>=n)
goto next;
}

while(k<=l)
{ k++;
b+=4;
gotoxy(a,b);
printf("%d",ar[m++]);
if(m>=n)
goto next;
}
while(p<=q)
{
p++;
a-=4;
gotoxy(a,b);
printf("%d",ar[m++]);
if(m>=n)
goto next;

}
while(r<=s)
{
r++;
b-=4;
gotoxy(a,b);
printf("%d",ar[m++]);
if(m>=n)
goto next;
}
j+=2;
l+=2;
q+=2;
s+=2;
i=0;
k=0;
p=0;
r=0;

}
next:getch();
return 0;
}

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3 Answers  

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