Answer / susie

Answer :

Variable length argument lists

Answer / sagar arora

variable length argument lists,for more information checked
out in Dennis Ritchie book.u can write ur own printf.

Answer / navneet

using Variable length argument lists :
Let us see how

Use vprintf, vfprintf, or vsprintf.

Here is an "error" routine which prints an error message, preceded by the string "error: " and terminated with a newline:

#include <stdio.h>
#include <stdarg.h>

void
error(char *fmt, ...)
{
va_list argp;
fprintf(stderr, "error: ");
va_start(argp, fmt);
vfprintf(stderr, fmt, argp);
va_end(argp);
fprintf(stderr, "\n");
}
To use the older <varargs.h> package, instead of <stdarg.h>, change the function header to:

void error(va_alist)
va_dcl
{
char *fmt;
change the va_start line to

va_start(argp);
and add the line

fmt = va_arg(argp, char *);
between the calls to va_start and vfprintf. (Note that there is no semicolon after va_dcl.)

References: K&R II Sec. 8.3 p. 174, Sec. B1.2 p. 245; H&S Sec. 17.12 p. 337; ANSI Secs. 4.9.6.7, 4.9.6.8, 4.9.6.9 .

print a semicolon using Cprogram without using a semicolon any where in the C code in ur program!!

35 Answers   Tata Elxsi, TCS, VI eTrans,

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#include<stdio.h> main() { char s[]={'a','b','c','\n','c','\0'}; char *p,*str,*str1; p=&s[3]; str=p; str1=s; printf("%d",++*p + ++*str1-32); }

2 Answers   CNSI,

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Given only putchar (no sprintf, itoa, etc.) write a routine putlong that prints out an unsigned long in decimal.

6 Answers   Fusion Systems GmbH,

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main() { int i=400,j=300; printf("%d..%d"); }

3 Answers  

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main() { main(); }

1 Answers  

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func(a,b) int a,b; { return( a= (a==b) ); } main() { int process(),func(); printf("The value of process is %d !\n ",process(func,3,6)); } process(pf,val1,val2) int (*pf) (); int val1,val2; { return((*pf) (val1,val2)); }

1 Answers   Satyam,

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#define square(x) x*x main() { int i; i = 64/square(4); printf("%d",i); }

4 Answers   Google, HCL, Quick Heal, WTF,

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void main() { char ch; for(ch=0;ch<=127;ch++) printf(“%c %d \n“, ch, ch); }

1 Answers  

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main() { int i=1; while (i<=5) { printf("%d",i); if (i>2) goto here; i++; } } fun() { here: printf("PP"); }

1 Answers  

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Finding a number multiplication of 8 with out using arithmetic operator

8 Answers   Eyeball, NetApp,

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main() { char not; not=!2; printf("%d",not); }

1 Answers  

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main() { int k=1; printf("%d==1 is ""%s",k,k==1?"TRUE":"FALSE"); }

1 Answers  

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