Is it possible to type a name in command line without ant
quotes?
find A^B using Recursive function
Is it possible to type a name in command line without ant quotes?
4. Main() { Int i=3,j=2,c=0,m; m=i&&j||c&I; printf(“%d%d%d%d”,I,j,c,m); }
void func1(int (*a)[10]) { printf("Ok it works"); } void func2(int a[][10]) { printf("Will this work?"); } main() { int a[10][10]; func1(a); func2(a); } a. Ok it works b. Will this work? c. Ok it worksWill this work? d. None of the above
There were 10 records stored in “somefile.dat” but the following program printed 11 names. What went wrong? void main() { struct student { char name[30], rollno[6]; }stud; FILE *fp = fopen(“somefile.dat”,”r”); while(!feof(fp)) { fread(&stud, sizeof(stud), 1 , fp); puts(stud.name); } }
main() { int i; clrscr(); for(i=0;i<5;i++) { printf("%d\n", 1L << i); } } a. 5, 4, 3, 2, 1 b. 0, 1, 2, 3, 4 c. 0, 1, 2, 4, 8 d. 1, 2, 4, 8, 16
void main() { static int i=5; if(--i){ main(); printf("%d ",i); } }
struct Foo { char *pName; }; main() { struct Foo *obj = malloc(sizeof(struct Foo)); clrscr(); strcpy(obj->pName,"Your Name"); printf("%s", obj->pName); } a. Your Name b. compile error c. Name d. Runtime error
main() { char c=' ',x,convert(z); getc(c); if((c>='a') && (c<='z')) x=convert(c); printf("%c",x); } convert(z) { return z-32; }
Write a complete program that consists of a function that can receive two numbers from a user (M and N) as a parameter. Then print all the numbers between the two numbers including the number itself. If the value of M is smaller than N, print the numbers in ascending flow. If the value of M is bigger than N, print the numbers in descending flow. may i know how the coding look like?
how many processes will gate created execution of -------- fork(); fork(); fork(); -------- Please Explain... Thanks in advance..!
void main() { int i=5; printf("%d",i+++++i); }