Answer / susie

Answer :

ibj!gsjfoet

Explanation:

++*p++ will be parse in the given order

> *p that is value at the location currently pointed by p
will be taken

> ++*p the retrieved value will be incremented

> when ; is encountered the location will be incremented
that is p++ will be executed




Hence, in the while loop initial value pointed by p is ‘h’,
which is changed to ‘i’ by executing ++*p and pointer moves
to point, ‘a’ which is similarly changed to ‘b’ and so on.
Similarly blank space is converted to ‘!’. Thus, we obtain
value in p becomes “ibj!gsjfoet” and since p reaches ‘\0’
and p1 points to p thus p1doesnot print anything.

Answer / sourav punoriyar

checked in gcc.

it gives segmentation fault(core dump),in gcc...
because the char *p="hai friends",is a pointer pointing to
this string in the code section,(this string is present in
code section.)
now,
++*p=this is ++(*p)=h+1=i,and stores it in p,but data in
code section cannot be modified so core dump.
if
*p++,first dereference and then increases the pointer....so
it will point to a now.

Answer / sourav punoriyar

but in turbo c it can be the given ans ,as given by susie,
as there it gets stored in datasection which is modifiable

struct Foo { char *pName; char *pAddress; }; main() { struct Foo *obj = malloc(sizeof(struct Foo)); clrscr(); obj->pName = malloc(100); obj->pAddress = malloc(100); strcpy(obj->pName,"Your Name"); strcpy(obj->pAddress, "Your Address"); free(obj); printf("%s", obj->pName); printf("%s", obj->pAddress); } a. Your Name, Your Address b. Your Address, Your Address c. Your Name Your Name d. None of the above

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write a program to count the number the same (letter/character foreg: 's') in a given sentence.

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main() { char *p="hai friends",*p1; p1=p; while(*p!='\0') ++*p++; printf("%s %s",p,p1); }

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void main() { static int i=i++, j=j++, k=k++; printf(“i = %d j = %d k = %d”, i, j, k); }

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#define a 10 void foo() { #undef a #define a 50 } int main() { printf("%d..",a); foo(); printf("%d..",a); return 0; } explain the answer

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main() { int i=10,j=20; j = i, j?(i,j)?i:j:j; printf("%d %d",i,j); }

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Write a C program to print look and say sequence? For example if u get the input as 1 then the sequence is 11 21 1211 111221 312211 12112221 .......(it counts the no. of 1s,2s etc which is in successive order) and this sequence is used in run-length encoding.

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How to swap two variables, without using third variable ?

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Is the following code legal? void main() { typedef struct a aType; aType someVariable; struct a { int x; aType *b; }; }

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