Answer / priti rachana

#include<stdio.h>
#include<conio.h>
void main()
{
int p,q,m,n,c;
int a1[100],a2[100],a3[100];
puts("enter the number of elements of the 1st sorted array");
scanf("%d",&p);
puts("enter number ofthe 1st sorted array");
for(m=0;<=p-1;m++)
scanf("%d",&a1[m]);
puts("enter number of element of the 2nd sorted array");
scanf("%d",&q);
puts(enter element of the 2nd sorted array");
for(n=0;n<=q-1;n++)
scanf("%d",&a2[n]);
c=0;
m=0;
n=0;
while((m<p)&&(n<q))
{
if(a1[m]<=a2[n])
a3[c]=a1[m++];
else
a3[c]=a2[n++];
c++;
}
while(m<p)
{
a3[c]=a2[n];
c++;
n++;
}
puts("merged array in asending order");
for(m=0;m<=c-1;m++)
printf("%d\n",a3[m]);
}

puts("enter the number of elements in the 2nd sorted arra array");
scanf("%d",&q);

Answer / ashok kannan

#include<stdio.h>
void main()
{
int a[]={1,1,2,3,4,5},b[]={2,3,4,5,6};
int i,j;
for(i=0;a[i]!='\0';i++);

for(j=0;b[j]!='\0';j++)
{
a[i]=b[j];
i++;
}

for(i=0;a[i]!='\0';i++)
printf("%d",a[i]);

}

main() { int i=300; char *ptr = &i; *++ptr=2; printf("%d",i); }

4 Answers   CSC,

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void main() { if(~0 == (unsigned int)-1) printf(“You can answer this if you know how values are represented in memory”); }

1 Answers  

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3) Int Matrix of certain size was given, We had few valu= es in it like this. =97=97=97=97=97=97=97=97=97=97=97 1 = | 4 | | 5 | &= nbsp; | 45 =97=97=97=97=97=97=97=97=97=97=97 &n= bsp; | 3 | 3 | 5 | = | 4 =97=97=97=97=97=97=97=97=97=97=97 34 |&nbs= p; 3 | 3 | | 12 | &= nbsp; =97=97=97=97=97=97=97=97=97=97=97 3 | &nbs= p; | 3 | 4 | = | 3 =97=97=97=97=97=97=97=97=97=97=97 3 | = ; | | | = ; 3 | =97=97=97=97=97=97=97=97=97=97=97 &= nbsp; | | 4 | = ; | 4 | 3 We w= ere supposed to move back all the spaces in it at the end. Note: = If implemented this prog using recursion, would get higher preference.

0 Answers   RoboSoft,

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#define DIM( array, type) sizeof(array)/sizeof(type) main() { int arr[10]; printf(“The dimension of the array is %d”, DIM(arr, int)); }

1 Answers  

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main() { float i=1.5; switch(i) { case 1: printf("1"); case 2: printf("2"); default : printf("0"); } }

2 Answers  

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main() { int i, j; scanf("%d %d"+scanf("%d %d", &i, &j)); printf("%d %d", i, j); } a. Runtime error. b. 0, 0 c. Compile error d. the first two values entered by the user

2 Answers   HCL,

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main() { int x=5; clrscr(); for(;x==0;x--) { printf("x=%d\n”", x--); } } a. 4, 3, 2, 1, 0 b. 1, 2, 3, 4, 5 c. 0, 1, 2, 3, 4 d. none of the above

3 Answers   HCL,

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main() { int c=- -2; printf("c=%d",c); }

1 Answers   TCS,

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main() { int c[ ]={2.8,3.4,4,6.7,5}; int j,*p=c,*q=c; for(j=0;j<5;j++) { printf(" %d ",*c); ++q; } for(j=0;j<5;j++){ printf(" %d ",*p); ++p; } }

2 Answers   CSS, Wipro,

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What is the match merge ? compare data step match merge with proc sql merge - how many types are there ? data step vs proc sql

0 Answers  

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struct Foo { char *pName; char *pAddress; }; main() { struct Foo *obj = malloc(sizeof(struct Foo)); clrscr(); obj->pName = malloc(100); obj->pAddress = malloc(100); strcpy(obj->pName,"Your Name"); strcpy(obj->pAddress, "Your Address"); free(obj); printf("%s", obj->pName); printf("%s", obj->pAddress); } a. Your Name, Your Address b. Your Address, Your Address c. Your Name Your Name d. None of the above

2 Answers   HCL,

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main() { if (!(1&&0)) { printf("OK I am done."); } else { printf("OK I am gone."); } } a. OK I am done b. OK I am gone c. compile error d. none of the above

3 Answers   HCL,

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