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void main()
{
static int i=5;
if(--i){
main();
printf("%d ",i);
}
}
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Answer / susie
Answer :
0 0 0 0
Explanation:
The variable "I" is declared as static, hence memory for I
will be allocated for only once, as it encounters the
statement. The function main() will be called recursively
unless I becomes equal to 0, and since main() is recursively
called, so the value of static I ie., 0 will be printed
every time the control is returned.
| Is This Answer Correct ? | 4 Yes | 5 No |
I need your help, i need a Turbo C code for this problem.. hope u'll help me guys.? Your program will have a 3x3 array. The user will input the sum of each row and each column. Then the user will input 3 values and store them anywhere, or any location or index, temporarily in the array. Your program will supply the remaining six (6) values and determine the exact location of each value in the array. Example: Input: Sum of row 1: 6 Sum of row 2: 15 Sum of row 3: 24 Sum of column 1: 12 Sum of column 2: 15 Sum of column 3: 18 Value 1: 3 Value 2: 5 Value 3: 6 Output: Sum of Row 1 2 3 6 4 5 6 15 7 8 9 24 Sum of Column 12 15 18 Note: Your program will not necessary sort the walues in the array Thanks..
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C Code 
