Answer / susie

Answer :

556

Explanation:

The integer value 300 in binary notation is: 00000001
00101100. It is stored in memory (small-endian) as:
00101100 00000001. Result of the expression *++ptr = 2 makes
the memory representation as: 00101100 00000010. So the
integer corresponding to it is 00000010 00101100 => 556.

Answer / subrat

556

Answer / giri

cannot convert int * to char * in main

Answer / bidhu

I think the answer depends on compiler.

In Dev-C++ the result is cannot convert int* to char* error

In Code:Block it gives a warning but gives the result 556

main() { clrscr(); } clrscr();

2 Answers  

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main() { int c[ ]={2.8,3.4,4,6.7,5}; int j,*p=c,*q=c; for(j=0;j<5;j++) { printf(" %d ",*c); ++q; } for(j=0;j<5;j++){ printf(" %d ",*p); ++p; } }

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void main() { char ch; for(ch=0;ch<=127;ch++) printf(“%c %d \n“, ch, ch); }

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main() { char *cptr,c; void *vptr,v; c=10; v=0; cptr=&c; vptr=&v; printf("%c%v",c,v); }

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main() { char *p; printf("%d %d ",sizeof(*p),sizeof(p)); }

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what is oop?

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union u { union u { int i; int j; }a[10]; int b[10]; }u; main() { printf("\n%d", sizeof(u)); printf(" %d", sizeof(u.a)); // printf("%d", sizeof(u.a[4].i)); } a. 4, 4, 4 b. 40, 4, 4 c. 1, 100, 1 d. 40 400 4

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How do you write a program which produces its own source code as its output?

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