Answer Posted / susie

Answer :

ibj!gsjfoet

Explanation:

++*p++ will be parse in the given order

> *p that is value at the location currently pointed by p
will be taken

> ++*p the retrieved value will be incremented

> when ; is encountered the location will be incremented
that is p++ will be executed




Hence, in the while loop initial value pointed by p is ‘h’,
which is changed to ‘i’ by executing ++*p and pointer moves
to point, ‘a’ which is similarly changed to ‘b’ and so on.
Similarly blank space is converted to ‘!’. Thus, we obtain
value in p becomes “ibj!gsjfoet” and since p reaches ‘\0’
and p1 points to p thus p1doesnot print anything.

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