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main()
{
char *p="hai friends",*p1;
p1=p;
while(*p!='\0') ++*p++;
printf("%s %s",p,p1);
}
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Answer Posted / sourav punoriyar
checked in gcc.
it gives segmentation fault(core dump),in gcc...
because the char *p="hai friends",is a pointer pointing to
this string in the code section,(this string is present in
code section.)
now,
++*p=this is ++(*p)=h+1=i,and stores it in p,but data in
code section cannot be modified so core dump.
if
*p++,first dereference and then increases the pointer....so
it will point to a now.
| Is This Answer Correct ? | 2 Yes | 0 No |
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