Answer / baiju k nair

the ideal earth resistance is 0 ohm.
but practically it
should be 1 ohms or less than that.

Answer / ramana

the resistance of the ideal earth is 0 ohm

Answer / utkal alumina

the ideal earth resistance is 0 ohm.but practically it
should be 1-2 ohms.

Answer / nagarjuna

IDLE EARTH RESISTANCE MEANS ZERO RESISTANCE.BUT THE EARTH RESISTANCE WIL NOT BE ZERO.THE EARTH RESISTANCE SHOULD BE LESS THAN 2 OHMS.

Answer / n.srinivasarao

Industrial is 0 ohms +/- .1%

Non industrial is 1 ohms

Answer / nagaraja

IDLE EARTH RESISTANCE MEANS ZERO RESISTANCE.BUT THE EARTH
RESISTANCE WIL NOT BE ZERO.THE EARTH RESISTANCE SHOULD BE
LESS THAN 2ohm,But indusealy earth resistance will
<5ohm.Grid resistance will be< 1ohm.

Answer / arun

ideal earth resistance is 0.5 ohms to 1 ohms.

Answer / tamjeed ahmad

the ideal earth resistance should be Zero..but nothing is
ideal in the "earth".
practicaly it should be less than 2 ohm.

Answer / arun

the resistance of the ideal earth is 0.5 ohm to 1ohms

Answer / praful nandankar

Ideally earth resistance should be zero. The range lies
between 0.5-2ohms.




praful

what are the safety in transformer,diesel generator,ups, chiller plant,h.t. , L.t. , sewage treatment plant(stp),water treatment plant(wtp), fire. plz ans. me in detail if you know any of the mention above. i urgently need

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3 Answers  

What is the resistance of human body from head to toe?

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We have drive feeding an output contactor for a 5000 hp motor @ 5kV application. The motor FLA is 629amps x 1.25% service factor = 786.25 amps The cable that we current have in place between the drive and the output contactor is 350kcmil- MV-105 (parallel cables). Per the NEC table 310.60 (C) (69). This show the cable ampacity is at 615 amps per cable for a rating of 1230 amps. We have derated the cable for the cable tray and the multiple cables application and our calculations show that after the correction factor factor we are at 922amps. 1230 amps x .75% correction factor factor = 922.5 amps. The customer is driving us to then use another safety factor of .25% off of the already derated cable. Can you please provide a longhand calculation for your solution on this application?

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