Answer / lakshya mehra

void main()
{
int dec,rem,i=1;
long int bin=0;
printf("Enter the decimal number : ");
scanf("%d",&dec);
while(dec>0)
{
rem=dec%2;
dec=dec/2;
bin=bin+(i*rem);
i=i*10;
}
printf("The binary number is %l",bin);
getch();
}

Explanation:
The output variable bin is taken as long int bcoz it might
exceed the range of normal int.

e.g.
dec=25

Then

bin=(1*1)+(10*0)+(100*0)+(1000*1)+(10000*1)
=11001

Answer / @pravin.08

@sudha
ur code is abs right with a minor mistake.
main()
{
int num,rem,b=0,i=1;
printf("enter num");
scanf("%d",&num);
while(num)
{
rem=num%2;
num=num/2;
b=b+rem*i;
i=i*10;
}
printf("\n%d",b);

}

Answer / sachin kumar sharma

#include<stdio.h>
#include<conio.h>
void main()
{
int d,rem,i=1;
long int bin=0;
printf("Enter the decimal number : ");
scanf("%d",&d);
while(d>0)
{
rem=d%2;
d=d/2;
bin=bin+(i*rem);
i=i*10;
}
printf("The binary number is %ld",bin);
getch();
}
/* eg.
enter decimal no 10
binary no is 1010

Answer / nimesh soni

#include<stdio.h>
void main()
{
long int no,i,k,andmask;
printf("Entre No ");
scanf("%ld",&no);
for(i=15;i>=0;i--)
{
andmask=1<<i;
k=no & andmask;
k==0 ? printf("0 ") : printf("1 ");
}
}

Answer / tushar srivastava

//A very Powerful method just a bit of tweaking done here
#include<iostream.h>
#include<conio.h>
void main()
{
unsigned long dec,rem,i=1;
unsigned long bin=0;//remember to set it to zero
cout<<"Enter a decimal number : ";
cin>>dec;
while(dec>0)
{
rem=dec%2;
dec=dec/2;
bin=bin+(i*rem);
i=i*10;
}
cout<<"The binary form is "<<bin;
getch();
clrscr();
}

//this method is tested by me it worked till 1023 but not
over it
//but it's fine right......

Answer / pritesh2444

#include<stdio.h>
void main()
{
int n,j=0,i=1;
printf("\nEnter the number : ");
scanf("%d",&n);
while(n!=0)
{
j=j+((n%2)*i);
n=n/2;
i=i*10;
}
printf("%d",j);
}

Answer / tushar srivastava

Hi Friends, This is Tushar Srivastava once again. This time
I have a program which is compatible with real world bit
level communication, since I have used the VC++'s 'bool'
keyword which can store only since bit of data. Take aa look
at this simple algorithm purely developed by me.
Please note that this program has used VC++'s 'bool' keyword
which will not be available with Turbo C++ 16 bit IDE (Old
DOS Mode).
Thank you.

// Bit Converter.cpp : This Program is a simple decimal to
binary converter
//This is a demonstration program which demonstrate the
method to convert any integer data into it's binary equivalent
//The algorithm is made be Tushar Srivastava independent of
any other person working on same method.
//This program is available to users under General Public
License.

#include "stdafx.h"
#include <stdio.h>
#include <conio.h>

int i;
bool bits(int bit_data);
int main()
{
int input_data=0;
bool bit=0;
printf("Please Enter the data to be converted :");
scanf("%d",&input_data);
for(i=15;i>=0;i--)
{
bit = bits(input_data);
printf("%d",bit);
}
getch();
return 0;
}

bool bits(int bit_data)
{
int temp_var;
temp_var = bit_data >> i;
temp_var &= 0x01;
return temp_var;
}

Answer / pritesh

#include<stdio.h>
void main()
{
int j=0,n,i=1;
printf("\nenter no.=");
scanf("%d",&n);
while(n!=0)
{
j=j+((n%2)*i);
n=n/2;
i=i*10;
}
printf("%d",j);
}

Answer / mritunjay kumar

void main()
{
int no,i=1,r,bin=0;
printf("enter a decimal no:-");
scanf("%d",&no);
clrscr();
while(no!=0)
{
r=no%2;
no=no/2;
bin=bin+(r*i);
i=i*10;
}
printf("converted no%d",bin);
getch();
}

Answer / rupam

#include<stdio.h>
#include<conio.h>
main(){
int dec,i,c,rem,bin[16];
c=0;
printf("\n \t Enter the Value : ");
scanf("%d",&dec);
while(dec!=0){
rem=dec%2;
bin[c]=rem;
dec=dec/2;
c++;
}
printf("\n \t Binary Equivalent : ");
for(i=(c-1);i>=0;i--){
printf("%d",bin[i]);
}
getch();
}

void main() { int i=5,y=3,z=2,ans; clrscr(); printf("%d",++i + --z + i++ + --i * ++y); i=5,y=3,z=2; ans=++i + --z + i++ + --i * ++y; printf("\n%d",ans); getch(); } Its output is 37 and 31.... Please explain me why its different How it works.....

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