Interested to Buy Any Domain ? << Click Here >> for more details...
#include<stdio.h>
void main()
{
int i=1;
printf("%d%d%d",i++,++i,i);
}
- 19 Answers
- 34214 Views
- I also Faced
- E-Mail Answers
Answers were Sorted based on User's Feedback
Answer / medo
221...
In printf() function compiler calculates the values from
right to left,but prints the values from left to right.
| Is This Answer Correct ? | 28 Yes | 13 No |
Answer / samrat
The Ans is: 2,3,3
In printf() the evaluation starts from right and the
printing of the values start from left.
Coming from right, the initial value is 1, after that ++i
will increment the value of i to 2. Now i++ will not be
incremented now. It will be incremented after the first "i"
is printed.
So we print 2 first, then the value of i is incremented to 3
(by executing i++). So for the other two i's the value will
be 3. So the ans is 2,3,3
| Is This Answer Correct ? | 13 Yes | 6 No |
Basically in printf the values are calcualted from right to left...and the output is displayed from left to right.
so the output will be
221
first one will be printed
then one will be incremented by one and made as two..since it is a pre increment and will be printed..
then the value now is 2..so it will be printed then it will be incremented { post increment }..
good question..
a typical example for working of Printf
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / prem_mallappa
The right answer is : Unpredictable/implementation defined behaviour.
Why? : get a C faq's book or visit online at c-faq.org
Reason: variable 'i' is changed more thane once between 'sequence point', a sequence point is a semicolon in 'C'. in such cases the result is unknown or compiler dependent.
| Is This Answer Correct ? | 1 Yes | 0 No |
I AM RICKY DOBRIYAL
THIS ANSWER IS DEFINETLY CORRECT
221
BECAUSE COMPILER CALCULATE RIGHT TO LEFT
| Is This Answer Correct ? | 2 Yes | 1 No |
Answer / mementomori76
answer is 221, but you shouldn't use void main
it's better to use int main()
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / rakesh
121
the first value is post increment(++i) and so at the first compilation the value is not incremented.. the next value is pre increment(i++) so it is incremented at the first compile. the third is the same as the input.
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / shahenshah07
its o/p:2 2 1
cause when parameter pass to any f'n its stored in a
stack(lifo).dats y its print i,++i;i++ respectively.
| Is This Answer Correct ? | 0 Yes | 0 No |
How to create a program that lists countries capitals when country is entered? (Terribly sorry, I'm a complete novist to coding with C, am looking for inspiration and general tips on how to code and create this program.)
Assume that the int variables i and j have been declared, and that n has been declared and initialized. Write code that causes a "triangle" of asterisks of size n to be output to the screen. Specifically, n lines should be printed out, the first consisting of a single asterisk, the second consisting of two asterisks, the third consistings of three, etc. The last line should consist of n asterisks. Thus, for example, if n has value 3, the output of your code should be * ** *** You should not output any space characters. Hint: Use a for loop nested inside another for loop.
write a profram for selection sort whats the error in it?
Given an int variable n that has been initialized to a positive value and, in addition, int variables k and total that have already been declared, use a do...while loop to compute the sum of the cubes of the first n whole numbers, and store this value in total . Thus if n equals 4, your code should put 1*1*1 + 2*2*2 + 3*3*3 + 4*4*4 into total . Use no variables other than n , k , and total .
class test { int a; public: test(int b):a(b){} void show(){ cout<<a; } }; void main() { test t1; test t2(5); t1.show(); t2.show(); } }
what is syntax error?
What is the out put of this programme? int a,b,c,d; printf("Enter Number!\n"); scanf("%d",&a); while(a=!0) { printf("Enter numbers/n"); scanf("%d%d%d",&b,&c,&d); a=a*b*c*d; } printf("thanks!"); getche(); Entering numbers are a=1,b=2,c=3,d=4 b=3,c=4,d=-5 b=3,c=4,d=0
Given that two int variables, total and amount, have been declared, write a loop that reads integers into amount and adds all the non-negative values into total. The loop terminates when a value less than 0 is read into amount. Don't forget to initialize total to 0. Instructor's notes: This problem requires either a while or a do-while loop.
A sample program using data structure? what is file handling?
Declaration of Cube Guys please help me.. Is this a right way to declare cube.? If i Compile it. It Says: Cube undeclared what should i do? Please help \thanks in advanced #include<stdio.h> #include<math.h> #include<conio.h> main( ) { float x,y; while(x++<10.0) { printf("Enter Number:"); scanf("%d", &x); y = cube(x); printf("%f %f %f \n", x,pow(x,2),y); cube(x); } { float x; float y; y = x*x*x; } getch(); return (y); }
void main() { for(int i=0;i<5;i++); printf("%d",i); } What is the output?..
32 Answers College School Exams Tests, CTS, HCL, iGate, SmartData,
difference between c/c++ programing language? what is necessesity of c++ when existing c programing language?
C C++ Errors 
