#include<stdio.h> void main() { int i=1; printf("%d%d%d",i

Categories >> ERRORS >> C C++ Errors
Suggest New Category

#include<stdio.h>
void main()
{
int i=1;
printf("%d%d%d",i++,++i,i);
}

Question Posted / medo

19 Answers
34864 Views
I also Faced
E-Mail Answers

Answers were Sorted based on User's Feedback

#include<stdio.h> void main() { int i=1; printf("%d%d%d",i++,++i,i); }..

Answer / medo

221...
In printf() function compiler calculates the values from
right to left,but prints the values from left to right.

Is This Answer Correct ?

28 Yes

13 No

#include<stdio.h> void main() { int i=1; printf("%d%d%d",i++,++i,i); }..

Answer / abhishek singh

221 is correct answer

Is This Answer Correct ?

12 Yes

5 No

#include<stdio.h> void main() { int i=1; printf("%d%d%d",i++,++i,i); }..

Answer / samrat

The Ans is: 2,3,3

In printf() the evaluation starts from right and the
printing of the values start from left.

Coming from right, the initial value is 1, after that ++i
will increment the value of i to 2. Now i++ will not be
incremented now. It will be incremented after the first "i"
is printed.

So we print 2 first, then the value of i is incremented to 3
(by executing i++). So for the other two i's the value will
be 3. So the ans is 2,3,3

Is This Answer Correct ?

13 Yes

6 No

#include<stdio.h> void main() { int i=1; printf("%d%d%d",i++,++i,i); }..

Answer / venkat

Basically in printf the values are calcualted from right to left...and the output is displayed from left to right.
so the output will be
221
first one will be printed
then one will be incremented by one and made as two..since it is a pre increment and will be printed..
then the value now is 2..so it will be printed then it will be incremented { post increment }..

good question..
a typical example for working of Printf

Is This Answer Correct ?

1 Yes

0 No

#include<stdio.h> void main() { int i=1; printf("%d%d%d",i++,++i,i); }..

Answer / prem_mallappa

The right answer is : Unpredictable/implementation defined behaviour.
Why? : get a C faq's book or visit online at c-faq.org

Reason: variable 'i' is changed more thane once between 'sequence point', a sequence point is a semicolon in 'C'. in such cases the result is unknown or compiler dependent.

Is This Answer Correct ?

1 Yes

0 No

#include<stdio.h> void main() { int i=1; printf("%d%d%d",i++,++i,i); }..

Answer / ricky/sonu dobriyal

I AM RICKY DOBRIYAL
THIS ANSWER IS DEFINETLY CORRECT
221
BECAUSE COMPILER CALCULATE RIGHT TO LEFT

Is This Answer Correct ?

2 Yes

1 No

#include<stdio.h> void main() { int i=1; printf("%d%d%d",i++,++i,i); }..

Answer / medo

what is the the output....?
and why?

Is This Answer Correct ?

5 Yes

5 No

#include<stdio.h> void main() { int i=1; printf("%d%d%d",i++,++i,i); }..

Answer / mementomori76

answer is 221, but you shouldn't use void main
it's better to use int main()

Is This Answer Correct ?

0 Yes

0 No

#include<stdio.h> void main() { int i=1; printf("%d%d%d",i++,++i,i); }..

Answer / rakesh

121
the first value is post increment(++i) and so at the first compilation the value is not incremented.. the next value is pre increment(i++) so it is incremented at the first compile. the third is the same as the input.

Is This Answer Correct ?

0 Yes

0 No

#include<stdio.h> void main() { int i=1; printf("%d%d%d",i++,++i,i); }..

Answer / shahenshah07

its o/p:2 2 1
cause when parameter pass to any f'n its stored in a
stack(lifo).dats y its print i,++i;i++ respectively.

Is This Answer Correct ?

0 Yes

0 No

Post New Answer

More C C++ Errors Interview Questions

What are the different types of errors in C and when they occur?

4 Answers

Given that two int variables, total and amount, have been declared, write a loop that reads integers into amount and adds all the non-negative values into total. The loop terminates when a value less than 0 is read into amount. Don't forget to initialize total to 0. Instructor's notes: This problem requires either a while or a do-while loop.

3 Answers

#include"stdio.h" #include"conio.h" void main() { int a; printf("\n enter a number:"); scanf("%c\n"); getch(); }

12 Answers HCL,

How to create a program that lists the capital country when told what the original country is? (Terribly sorry, I'm a novice programmer and would appreciate any help ;). Cheers, Alexxis

0 Answers

main() { char c; for(c='A';c<='Z';c++) getch(); }

9 Answers

quoroum of computer languages?

0 Answers Infosys,

when i use cout or cin call & then either << or >> .....it shows declaration syntax error...what should i do? cout<<"anything"; int a; cin>>a; return 0;

2 Answers

char* f() return "hello:"; void main() {char *str=f(); }

1 Answers

what is meant by linking error? how can i solve it? if there is a linking error " unable to open file 'cos.obj'? then what should i do?

1 Answers

Write a c-programe that input one number of four digits and find digits sum?

2 Answers

#include<iostream.h> #include<stdlib.h> static int n=0; class account { int age,accno; float amt; char name[20]; public: friend void accinfo(account [] ,int); void create(); void balenq(); void deposite(); void withdrawal(); void transaction(account []); }; void account :: create() { static int acc=1231; accno=acc+n; cout<<"\n\tENTER THE CUSTOMER NAME : "; cin>>name; cout<<"\n\t ENTER THE AGE : "; cin>>age; cout<<"\n\t ENTER THE AMOUNT : "; cin>>amt; // if(amt<=500) // cout<<"\n\tAMOUNT IS NOT SUFFICIENT TO CREATE AN ACCOUNT..."; cout<<"\n\t YOUR ACCOUNT NUMBER : "<<accno<<endl; n++; } void accinfo(account cus[],int ch) { int no,flag=0; cout<<"\n\t\tENTER YOUR ACCOUNT NUMBER : "; cin>>no; for(int i=0;i<=n&&flag==0;i++) if(no==cus[i].accno) { flag=1; switch(ch) { case 2: cus[i].balenq(); break; case 3: cus[i].deposite(); break; case 4: cus[i].withdrawal(); break; case 5: cus[i].transaction(cus); break; default: cout<<"\n\t\tEND OF THE OPERATION"; exit(1); } } if(flag==0) cout<<"\n\t\tYOUR ACCOUNT DOES NOT EXIST..."<<endl; } void account :: balenq() { cout<<"\n\t\tCUSTOMER NAME : "<< name << endl; cout<<"\n\t\tBALANCE : "<< amt << endl; } void account :: deposite() { int damt; cout<<"\n\t\tCUSTOMER NAME : "<< name <<endl; cout<<"\n\t\tBALANCE : "<< amt <<endl; cout<<"\n\tENTER THE AMOUNT TO BE DEPOSITED : "; cin>>damt; amt+=damt; cout<<"\n\t\tYOUR CURRENT BALANCE : "<<amt<<endl; } void account :: withdrawal() { int wamt; cout<<"\n\t\tCUSTOMER NAME : "<< name; cout<<"\n\t\tBALANCE : "<< amt; cout<<"\n\tENTER THE AMOUNT TO BE WITHDRAWN : "; cin>>wamt; if(amt-wamt>=500) { amt-=wamt; cout<<"\n\t\tYOUR CURRENT BALANCE : "<<amt; } else cout<<"\n\tYOUR BALANCE IS TOO LOW FOR WITHDRAWAL..."<<endl; } void account :: transaction (account cus[]) { int no,tamt,flag=0; cout<<"\n\tENTER THE RECEIVER'S ACCOUNT NUMBER : "; cin>>no; cout<<"\n\t\t ENTER THE AMOUNT : "; cin>>tamt; for(int i=0;i<=n&&flag==0;i++) if(cus[i].accno==no) { flag=1; cus[i].amt+=tamt; amt-=tamt; cout<<"\n\t\tYOUR CURRENT BALANCE : "<<amt<<endl; cout<<"\n\t\t RECEIVER'S BALANCE : "<<cus[i].amt<<endl; } if(flag==0) cout<<"\n\tRECEIVER'S ACCOUNT NUMBER IS NOT AVALIABLE..."<<endl; } void main() { account cus[10]; int ch; do { cout<<"\n\t\t BANK ACCOUNT"; cout<<"\n\t\t ************\n"; cout<<"\n\t\t1.CREATE AN ACCOUNT"; cout<<"\n\t\t2.BALANCE ENQUIRY"; cout<<"\n\t\t3.DEPOSITE"; cout<<"\n\t\t4.WITHDRAWAL"; cout<<"\n\t\t5.TRANSACTION"; cout<<"\n\t\t6.EXIT\n\n"; cout<<"\n\t\tENTER YOUR CHOICE : "; cin>>ch; if(ch==1) cus[n].create(); else accinfo(cus,ch); }while(1); }

1 Answers

what is syntax error?

3 Answers

For more C C++ Errors Interview Questions Click Here