Answer / joshin

//program for selection sort
#include<stdio.h>
#include<conio.h>
#define MX 100
void selection(int [], int);
void selection(int a[],int n)
{
int minindx,t;
int i,j;
for(i=0;i<n-1;i++)
{
minindx=i;
for(j=i+1;i<n;j++)
{
if(a[j]<a[minindx])
minindx=j;
}
if(minindx!=i)
{
t=a[i];
a[i]=a[minindx];
a[minindx]=t;
}
}
}
void main()
{
int a[MX],i,n;
clrscr();
printf("enter total num of elements:");
scanf("%d",&n);
for(i=0;i<n;i++)
{
scanf("%d",&a[i]);
}
selection(a,n);
printf("sorted arrau:\n");
for(i=0;i<n;i++)
{
printf("%d \t",a[i]);
}
getch();
}

Answer / alam

#include<iostream>
using namespace std;
int main()
{
int i,t,j,min,n=0,m=0;
int a[6]={6,3,2,10,5,8};
//0 1 2 3 4 5
for(i=0;i<=13;i++)
{
m++;
min=i;
for(j=i+1;j<=5;j++)
{
if(a[j]<a[min])
min=j;
n++;
}
t=a[i];
a[i]=a[min];
a[min]=t;
}
cout<<"******Selection Sort*********"<<endl;
for(i=0;i<=5;i++)
{
cout<<"a["<<i<<"]="<<a[i]<<endl;
}

cout<<"Outer Loop Total count :"<<m<<endl;
cout<<"Inner Loop Total count :"<<n<<endl;


return 0;
}

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