Answer / mani

#include<stdio.h>
void main()
{
char *str1[10],*str2[10],str3[10],str[4];
boolean check1,check2;
int i=0,j=1;
do
printf("enter the first string of odd length");
scanf("%s",str1);
printf("enter the second string of odd length");
scanf("%s",str2);
check1=testlen(&str1);
check2=testlen(&str2);
}
while(check1!=true && check2!=true);

while( *str1!='/o' || *str2!='/o')
{
if(str1[i]!='/o)
str3[i]=str1[i];

if(str2[i]!='/o)
str3[i+1]=str2[i];

i+=2;
}

while( *str1!='/o' || *str2!='/o')
{
if(str1[j]!='/o)
str4[j]=str1[j];

if(str2[j]!='/o)
str4[j+1]=str2[j];

i+=2;
}
printf("The value of string1 is %s",str1);
printf("The value of string1 is %s",str2);
printf("The value of string1 is %s",str3);
printf("The value of string1 is %s",str4);

}

boolean testlen(char *c) //function
{
int count;
while(*c++!='/o')
count++;
if(count%2!=0)
return true;
else
return false;
}

what is syntax error?

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