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how to convert decimal to binary in c using while loop
without using array
- 50 Answers
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Answer / casona the hunter
/* To Convert Using While Loop/*
#include <stdio.h>
#include<conio.h>
int main(void)
{
int Bin, Dec,Octal,Hexa,ans;
int rem[10],x=0;
char ch;
clrscr();
printf("B- - -Decimal-B\n\n");
printf("O- - -Decimal-O\n\n");
printf("H- - -Decimal-H\n\n");
printf("E- - -Exit\n\n");
printf("Choice:");
scanf("%c",& ch);
switch (ch)
{
case 'b': clrscr();
printf("Enter Decimal.:");
scanf("%d",& Dec);
while(Dec!=0)
{
rem[x] = Dec%2;
Dec = Dec/2;
x++;
}
x = x-1;
while (x>=0)
{
printf("%i",rem[x]);
x--;
}
}
getch();
return 0;
}
| Is This Answer Correct ? | 21 Yes | 33 No |
Answer / vimal vijayakumar
A simple code for u....
#include<stdio.h>
void main()
{
int n,b;
printf("Enter a no");
scanf("%d",&n);
while(n>0)
{
b=n%2;
if(b==1)
printf("0");
else
printf("1");
n=n/2;
}
getch();
}
send ur feed back to --- vimal9446706153@gmail.com
| Is This Answer Correct ? | 18 Yes | 30 No |
Answer / kk
//in c++
#include<iostream.h>
#include<conio.h>
void conv(int n)
{
int a[100],i;
for(i=0;n!=0;i++)
{
a[i]=n%2;
n=n/2;
}
cout<<"the binary is";
for(i-=1;i>=0;i--)
{
cout<<a[i];
}
}
void main()
{
clrscr();
int n;
cout<<"enter the no:";
cin>>n;
conv(n);
getch();
}
| Is This Answer Correct ? | 2 Yes | 17 No |
Answer / nick
/* convert a decimal number to binary */
int dectobin(int dec)
{
int bin=0, i=1;
while(dec!=0)
{
bin+=(dec%2)*i;
dec=dec/2;
i*=10;
}
return bin;
}
| Is This Answer Correct ? | 24 Yes | 47 No |
Answer / sam
all these answers crap
when you
b = b+rem*i
b is filled with int number
and adds the next one to it in the loop
so it wont be as b= 10011001
it will be b= the number i have intered
you idiots ....
| Is This Answer Correct ? | 29 Yes | 56 No |
Answer / darhakz
#include<stdio.h>
#include<math.h>
#include<string.h>
int bin2dec(int decimal);
int main(void)
{
int num;
printf("The decimal equilavent is: %d", bin2dec(decimal));
getchar();
getchar();
return 0;
}
int bin2dec(int decimal)
{
int num[10];
int i;
int bin;
int arr1[10];
int arr2[10] = {512,256,128,64,32,16,8,4,2,1};
printf("Enter a binary(0's and 1's) number: ");
scanf("%d", &arr1);
This is qheere I get confused.
for (i = 0; i < arr1; i++)
{
if (arr1[i] == 1)
num[i] = arr1[i];
arr2[i]= num[i]
decimal = arr2[i];
}
return decimal;
}
| Is This Answer Correct ? | 15 Yes | 46 No |
Answer / ritcanz
Void main()
{
int dec,i=1,rem,res=0;
Printf("Enter the Value %d",&dec);
while(dec!=0)
{
rem=dec%2;
dec=dec/2;
res=res+(i * 1);
i=i*10;
}
printf("The Binary value is %d",res);
}
| Is This Answer Correct ? | 15 Yes | 48 No |
Answer / sachin
#include<stdio.h>
int main()
{
int n, rem, num, i=1;
printf("enter no\n");
scanf("%d", &n);
while(n>0 )
{
rem = n % 2;
n = n/2;
num = (rem * i)+num;
i = i * 10;
}
printf("binary no: %d", num);
}
| Is This Answer Correct ? | 57 Yes | 93 No |
Answer / sujeeshkrishnan
main()
{
int dec,rem,ans=0;
printf("Enter the number\n");
scanf("%d",&dec);
while(dec>=2)
{
rem=dec%2;
dec=dec/2;
if(rem==0)
ans=ans*10;
else
ans=(ans*10)+1;
}
printf("The binary number is");
while(ans>0)
{
rem=ans%10;
ans=ans/10;
printf("%d",rem);
}
getch();
return 0;
}
| Is This Answer Correct ? | 74 Yes | 163 No |
Answer / sudha
Void main()
{
int dec,i=1,rem,res=0;
Printf("Enter the Value %d",&dec);
while(dec!=0)
{
rem=dec%2;
dec=dec/2;
res=res+(i * 1);
i=i*10;
}
printf("The Binary value is %d",res);
}
| Is This Answer Correct ? | 154 Yes | 396 No |
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