how to convert decimal to binary in c using while loop
without using array
Answers were Sorted based on User's Feedback
Answer / tushar srivastava
Hello Friends,
I am having a question here....
If you can save a binary number in at maximum four bytes,
then why are you wasting 16 bytes for the same. This method
is not recommended by me lest you need to send data to some
output port. And even the previous method ie my method can
directly be used to transfer data though serial or parallel
port if needed. Ponder over it......
Is This Answer Correct ? | 2 Yes | 2 No |
Answer / praveenkumar
#include<stdio.h>
#include<conio.h>
void main()
{
long int dec,k=0,i=0,j=0,n,remainder,result[100];
printf("\n Enter any Value : ");
scanf("%ld",&dec);
while(dec>0)
{
remainder=dec%2;
result[k]=remainder;
k++;
dec=dec/2;
if(remainder==0)
{
i++;
}
else
{
j++;
}
}
printf("\n Binary : ");
for(n=k-1;n>=0;n--)
printf("%d",result[n]);
printf("\n 0's : %ld",i);
printf("\n 1's : %ld",j);
printf("\n Total Digits : %d",k);
getch();
}
Is This Answer Correct ? | 3 Yes | 3 No |
Answer / suresh
#include<stdio.h>
#include<conio.h>
void main()
{
int i,n;
clrscr();
scanf("%d",&n);
i=0;
while(i<=15)
{
printf("%d",(n<<i)&(1<<15)?1:0);
i++;
}
}
Is This Answer Correct ? | 0 Yes | 0 No |
Answer / bhagyashree
Q.How to convert to binary to decimal in c++ using array.
#include<iostream.h>
#include<conio.h>
void main()
{
clrscr();
int i,n,j[8]={1,2,4,8,16,32},k=0;
int num[10],num1[10],s=0;
cout<<"Enter total num of digit:";
cin>>n;
for(i=0;i<n;i++)
{
cout<<"\nEnter "<<i+1<<" position";
cin>>num[i];
}
for(i=n-1;i>=0;i--)
{
num1[i]=num[i]*j[k];
s=s+num1[i];
k++;
}
cout<<"s="<<s;
getch();
}
Is This Answer Correct ? | 0 Yes | 0 No |
Answer / deva
#include<stdio.h>
#include<conio.h>
#include<math.h>
void main()
{
long int bn,temp;
int dn=0,e=0,digit;
clrscr();
printf("Enter binary number in form of 0 and 1 : ");
scanf("%ld",&bn);
temp=bn;
while(bn!=0)
{
digit= bn%10;
dn+=digit*pow(2,e);
e++;
bn/=10;}
printf("Binary number = %ld \n",temp);
printf("Decimal number= %d \n",dn);
getch();}
Is This Answer Correct ? | 0 Yes | 0 No |
Answer / chiran ravani
#include<stdio.h>
int main(void) {
int n,i=7,bin;
printf("Enter a decimal no:");
scanf("%d",&n);
while(i>=0) {
bin=n>>i;
if(bin&1)
printf("1");
else
printf("0");
i--;
}
}
Is This Answer Correct ? | 0 Yes | 0 No |
Answer / chiran ravani
sorry friends please ignore the previous answer.
Is This Answer Correct ? | 0 Yes | 0 No |
Answer / zahid
Any body help me to write a program to convert decimal to binary without using loop
Is This Answer Correct ? | 0 Yes | 0 No |
Answer / govind kumar
#include<conio.h>
#include<stdio.h>
void main()
{
int n,b=0,d=1,r,i=1;
printf("enter any binary no");
scanf("%d",&b);
while(n>0)
{
r=n%2;
b=b+r*d;
d=d*10;
n=n/2;
}
printf("the binary no is=%d",b);
}
getch;
}
Is This Answer Correct ? | 0 Yes | 0 No |
Answer / purva
#include<stdio.h>
#include<conio.h>
void main()
{
int n,i=1,a,d=0,b=0,c;
clrscr();
printf("enter decimal no.");
scanf("%d",&n);
while(n!=0)
{
a=n%2;
n=n/2;
d=d*10+a;
i++;
}
printf("d=%d",d);
while(d!=0)
{
c=d%10;
d=d/10;
b=b*10+c;
i++;
}
printf("\n binary equivalent is=%d",b);
getch();
}
Is This Answer Correct ? | 0 Yes | 1 No |
#include"stdio.h" #include"conio.h" void main() { int a; printf("\n enter a number:"); scanf("%c\n"); getch(); }
#include<stdio.h> void main() { int i=1; printf("%d%d%d",i++,++i,i); }
main() { char c; for(c='A';c<='Z';c++) getch(); }
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