Answer / tushar srivastava

Hello Friends,
I am having a question here....
If you can save a binary number in at maximum four bytes,
then why are you wasting 16 bytes for the same. This method
is not recommended by me lest you need to send data to some
output port. And even the previous method ie my method can
directly be used to transfer data though serial or parallel
port if needed. Ponder over it......

Answer / praveenkumar

#include<stdio.h>
#include<conio.h>
void main()
{
long int dec,k=0,i=0,j=0,n,remainder,result[100];
printf("\n Enter any Value : ");
scanf("%ld",&dec);
while(dec>0)
{
remainder=dec%2;
result[k]=remainder;
k++;
dec=dec/2;
if(remainder==0)
{
i++;
}
else
{
j++;
}
}
printf("\n Binary : ");
for(n=k-1;n>=0;n--)
printf("%d",result[n]);
printf("\n 0's : %ld",i);
printf("\n 1's : %ld",j);
printf("\n Total Digits : %d",k);
getch();
}

Answer / suresh

#include<stdio.h>
#include<conio.h>
void main()
{
int i,n;
clrscr();
scanf("%d",&n);
i=0;
while(i<=15)
{
printf("%d",(n<<i)&(1<<15)?1:0);
i++;
}
}

Answer / bhagyashree

Q.How to convert to binary to decimal in c++ using array.

#include<iostream.h>
#include<conio.h>
void main()
{
clrscr();
int i,n,j[8]={1,2,4,8,16,32},k=0;
int num[10],num1[10],s=0;
cout<<"Enter total num of digit:";
cin>>n;
for(i=0;i<n;i++)
{
cout<<"\nEnter "<<i+1<<" position";
cin>>num[i];
}
for(i=n-1;i>=0;i--)
{
num1[i]=num[i]*j[k];
s=s+num1[i];
k++;
}
cout<<"s="<<s;
getch();
}

Answer / deva

#include<stdio.h>
#include<conio.h>
#include<math.h>
void main()
{
long int bn,temp;
int dn=0,e=0,digit;
clrscr();
printf("Enter binary number in form of 0 and 1 : ");
scanf("%ld",&bn);
temp=bn;
while(bn!=0)
{
digit= bn%10;
dn+=digit*pow(2,e);
e++;
bn/=10;}
printf("Binary number = %ld \n",temp);
printf("Decimal number= %d \n",dn);
getch();}

Answer / chiran ravani

#include<stdio.h>
int main(void) {
int n,i=7,bin;
printf("Enter a decimal no:");
scanf("%d",&n);
while(i>=0) {
bin=n>>i;
if(bin&1)
printf("1");
else
printf("0");
i--;
}
}

Answer / chiran ravani

sorry friends please ignore the previous answer.

Answer / zahid

Any body help me to write a program to convert decimal to binary without using loop

Answer / govind kumar

#include<conio.h>
#include<stdio.h>
void main()
{
int n,b=0,d=1,r,i=1;
printf("enter any binary no");
scanf("%d",&b);
while(n>0)
{
r=n%2;
b=b+r*d;
d=d*10;
n=n/2;
}
printf("the binary no is=%d",b);
}
getch;
}

Answer / purva

#include<stdio.h>
#include<conio.h>
void main()
{
int n,i=1,a,d=0,b=0,c;
clrscr();
printf("enter decimal no.");
scanf("%d",&n);
while(n!=0)
{
a=n%2;
n=n/2;
d=d*10+a;
i++;
}
printf("d=%d",d);
while(d!=0)
{
c=d%10;
d=d/10;
b=b*10+c;
i++;
}
printf("\n binary equivalent is=%d",b);
getch();
}

loop1: { x=i<n?(i++):0; printf("%d",i); exit(x); continue; } Error- misplaced continue. Doubt-1.will the exit(x) be executed for all values of x 2.will this statement go out of the program.

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