Answer / sudha rani

An error that occurs during the execution of a program. In
contrast, compile-time errors occur while a program is
being compiled. Runtime errors indicate bugs in the program
or problems that the designers had anticipated but could do
nothing about. For example, running out of memory will
often cause a runtime error.
A runtime error is a computer error that appears in
the form of a message box consisting of a particular code
along with its corresponding definitions. Usually, a user
will notice that the computer becomes noticeably slow
before a runtime error appears.

After the runtime error message has been displayed and
closed, the software that shows this error would normally
close or freeze. In some cases, the operating system will
reboot.

Answer / venkat

run time error is the error which notify at the run time of
the program

Answer / sandeep palav

a run time error is a logical error....
it can be infinite looping, division by zero or an arrray
overflow.
such errors can be managed with implementing the exception
handling concept.

Answer / vipin bhatia

no doubt run time error occur while runtime.. but when the
execution of program take place and we enter input max then
limit or answer reach upto max data type lime , error
occured also known run time error....

Answer / santhosh

UsUally c program!THEY are two types?
complie!and run time?
compile means high level language&low level language into
middile level langage!this is complier!run time is program
code convert into machine code(binarys)some code are not
accept machine code!that also become runtime erroe!

Answer / ramya

During execution of the program the error will occur.it
produce wrong result and also go to main program

Answer / kalyank_msg

Run time error is occured only at runtime / execution time,
when we give the invalid input.

I am using Qt 5.6 during compilation it stops and gives error about Qmake The process "C:QtQt5.6.35.6.3msvc2015_64inqmake.exe" crashed. Error while building/deploying project untitled1 (kit: Desktop Qt 5.6.3 MSVC2015 64bit) When executing step "qmake"

0 Answers  

To generate the series 1+3+5+7+... using C program

18 Answers  

class test { int a; public: test(int b):a(b){} void show(){ cout<<a; } }; void main() { test t1; test t2(5); t1.show(); t2.show(); } }

1 Answers  

#include<>stdio.h> #include<>conio.h> { printf("hello"); void main() getch(); } what the out put of this program and why ......plz clear my answer

10 Answers   Wipro,

What is the out put of this programme? int a,b,c,d; printf("Enter Number!\n"); scanf("%d",&a); while(a=!0) { printf("Enter numbers/n"); scanf("%d%d%d",&b,&c,&d); a=a*b*c*d; } printf("thanks!"); getche(); Entering numbers are a=1,b=2,c=3,d=4 b=3,c=4,d=-5 b=3,c=4,d=0

5 Answers   TCS,

Why are memory errors hard to debug?

1 Answers  

Write a C program to enter 10 integer numbers through one variable and count how many of them are even using while loop ?

2 Answers  

void main() { int i=5,y=3,z=2,ans; clrscr(); printf("%d",++i + --z + i++ + --i * ++y); i=5,y=3,z=2; ans=++i + --z + i++ + --i * ++y; printf("\n%d",ans); getch(); } Its output is 37 and 31.... Please explain me why its different How it works.....

2 Answers  

I'm having trouble with coming up with the correct code. Do I need to put a loop? Please let me know if I'm on the right track and what areas I need to correct. I still don't have a good grasp on this programming stuff. Thanks =) The assignment was to write a program using string functions that accepts a coded value of an item and displays its equivalent tag price. The base of the keys: 0 1 2 3 4 5 6 7 8 9 X C O M P U T E R S Sample I/O Dialogue: Enter coded value: TR.XX Tag Price : 68.00

3 Answers   UCB,

Given an int variable n that has been initialized to a positive value and, in addition, int variables k and total that have already been declared, use a do...while loop to compute the sum of the cubes of the first n whole numbers, and store this value in total . Thus if n equals 4, your code should put 1*1*1 + 2*2*2 + 3*3*3 + 4*4*4 into total . Use no variables other than n , k , and total .

3 Answers  

#include<iostream.h> #include<stdlib.h> static int n=0; class account { int age,accno; float amt; char name[20]; public: friend void accinfo(account [] ,int); void create(); void balenq(); void deposite(); void withdrawal(); void transaction(account []); }; void account :: create() { static int acc=1231; accno=acc+n; cout<<"\n\tENTER THE CUSTOMER NAME : "; cin>>name; cout<<"\n\t ENTER THE AGE : "; cin>>age; cout<<"\n\t ENTER THE AMOUNT : "; cin>>amt; // if(amt<=500) // cout<<"\n\tAMOUNT IS NOT SUFFICIENT TO CREATE AN ACCOUNT..."; cout<<"\n\t YOUR ACCOUNT NUMBER : "<<accno<<endl; n++; } void accinfo(account cus[],int ch) { int no,flag=0; cout<<"\n\t\tENTER YOUR ACCOUNT NUMBER : "; cin>>no; for(int i=0;i<=n&&flag==0;i++) if(no==cus[i].accno) { flag=1; switch(ch) { case 2: cus[i].balenq(); break; case 3: cus[i].deposite(); break; case 4: cus[i].withdrawal(); break; case 5: cus[i].transaction(cus); break; default: cout<<"\n\t\tEND OF THE OPERATION"; exit(1); } } if(flag==0) cout<<"\n\t\tYOUR ACCOUNT DOES NOT EXIST..."<<endl; } void account :: balenq() { cout<<"\n\t\tCUSTOMER NAME : "<< name << endl; cout<<"\n\t\tBALANCE : "<< amt << endl; } void account :: deposite() { int damt; cout<<"\n\t\tCUSTOMER NAME : "<< name <<endl; cout<<"\n\t\tBALANCE : "<< amt <<endl; cout<<"\n\tENTER THE AMOUNT TO BE DEPOSITED : "; cin>>damt; amt+=damt; cout<<"\n\t\tYOUR CURRENT BALANCE : "<<amt<<endl; } void account :: withdrawal() { int wamt; cout<<"\n\t\tCUSTOMER NAME : "<< name; cout<<"\n\t\tBALANCE : "<< amt; cout<<"\n\tENTER THE AMOUNT TO BE WITHDRAWN : "; cin>>wamt; if(amt-wamt>=500) { amt-=wamt; cout<<"\n\t\tYOUR CURRENT BALANCE : "<<amt; } else cout<<"\n\tYOUR BALANCE IS TOO LOW FOR WITHDRAWAL..."<<endl; } void account :: transaction (account cus[]) { int no,tamt,flag=0; cout<<"\n\tENTER THE RECEIVER'S ACCOUNT NUMBER : "; cin>>no; cout<<"\n\t\t ENTER THE AMOUNT : "; cin>>tamt; for(int i=0;i<=n&&flag==0;i++) if(cus[i].accno==no) { flag=1; cus[i].amt+=tamt; amt-=tamt; cout<<"\n\t\tYOUR CURRENT BALANCE : "<<amt<<endl; cout<<"\n\t\t RECEIVER'S BALANCE : "<<cus[i].amt<<endl; } if(flag==0) cout<<"\n\tRECEIVER'S ACCOUNT NUMBER IS NOT AVALIABLE..."<<endl; } void main() { account cus[10]; int ch; do { cout<<"\n\t\t BANK ACCOUNT"; cout<<"\n\t\t ************\n"; cout<<"\n\t\t1.CREATE AN ACCOUNT"; cout<<"\n\t\t2.BALANCE ENQUIRY"; cout<<"\n\t\t3.DEPOSITE"; cout<<"\n\t\t4.WITHDRAWAL"; cout<<"\n\t\t5.TRANSACTION"; cout<<"\n\t\t6.EXIT\n\n"; cout<<"\n\t\tENTER YOUR CHOICE : "; cin>>ch; if(ch==1) cus[n].create(); else accinfo(cus,ch); }while(1); }

1 Answers  

what are the techniques for reducing the fragility of a memory bug?

1 Answers