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main()
{
char c;
for(c='A';c<='Z';c++)
getch();
}
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The initial condition is c='A'.
Here the the statement "getch();" is the body of the loop.
it is executed once and c becomes 'B' and again the loop is
executed.
This is done,I mean the loop is executed 26 times.
when c become 'Z' the loop is executed one more time(because
the condition is c<='Z')and then the program exit.
| Is This Answer Correct ? | 3 Yes | 1 No |
Answer / vignesh1988i
this wont show any errors since syntactically it is correct...
but since there is no instructions after for loop for operations unfortunelety getch() will be taken as the next instruction , and thus compiler system will be under ambiquity. since the character key pressed will be taken as the value of getch() so that will say to the OPERATING SYSTEM that compilation has got over and it will return to the IDE... but for loop has not got over.. so this depends on the compilers usage............
thank u
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / aaaaaaa
No Errors
loop will execute for 26 times,each time it will wait for an
input and finally terminate when c becomes > Z.
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / sambath
Answer : "It have no errors but it will be still running
mode until use cntrl+break.. using { and } we will avoid this."
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / abhishek rajput
Since A=65 and Z=90.
So each time getch will
encounter and user
need to press anykey
each time till c
increments to 90...
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / carlos
God help those who help themselves!
try it ur's self because i don't know about this programming
brother! i'm sorry forgive me.
| Is This Answer Correct ? | 2 Yes | 3 No |
Answer / bharghavi
if ther s no body for the 'for' loop,it should end with
semicolon..(i.e)
main()
{
char c;
for(c='A';c<='Z';c++);
getch();
}
or
main()
{
char c;
for(c='A';c<='Z';c++)
{}
getch();
}
| Is This Answer Correct ? | 6 Yes | 11 No |
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