Interested to Buy Any Domain ? << Click Here >> for more details...
main()
{
char c;
for(c='A';c<='Z';c++)
getch();
}
- 9 Answers
- 16970 Views
- I also Faced
- E-Mail Answers
Answers were Sorted based on User's Feedback
The initial condition is c='A'.
Here the the statement "getch();" is the body of the loop.
it is executed once and c becomes 'B' and again the loop is
executed.
This is done,I mean the loop is executed 26 times.
when c become 'Z' the loop is executed one more time(because
the condition is c<='Z')and then the program exit.
| Is This Answer Correct ? | 3 Yes | 1 No |
Answer / vignesh1988i
this wont show any errors since syntactically it is correct...
but since there is no instructions after for loop for operations unfortunelety getch() will be taken as the next instruction , and thus compiler system will be under ambiquity. since the character key pressed will be taken as the value of getch() so that will say to the OPERATING SYSTEM that compilation has got over and it will return to the IDE... but for loop has not got over.. so this depends on the compilers usage............
thank u
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / aaaaaaa
No Errors
loop will execute for 26 times,each time it will wait for an
input and finally terminate when c becomes > Z.
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / sambath
Answer : "It have no errors but it will be still running
mode until use cntrl+break.. using { and } we will avoid this."
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / abhishek rajput
Since A=65 and Z=90.
So each time getch will
encounter and user
need to press anykey
each time till c
increments to 90...
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / carlos
God help those who help themselves!
try it ur's self because i don't know about this programming
brother! i'm sorry forgive me.
| Is This Answer Correct ? | 2 Yes | 3 No |
Answer / bharghavi
if ther s no body for the 'for' loop,it should end with
semicolon..(i.e)
main()
{
char c;
for(c='A';c<='Z';c++);
getch();
}
or
main()
{
char c;
for(c='A';c<='Z';c++)
{}
getch();
}
| Is This Answer Correct ? | 6 Yes | 11 No |
#include<stdio.h> void main() { int i=1; printf("%d%d%d",i++,++i,i); }
write a profram for selection sort whats the error in it?
wap for bubble sort
#include<iostream.h> #include<stdlib.h> static int n=0; class account { int age,accno; float amt; char name[20]; public: friend void accinfo(account [] ,int); void create(); void balenq(); void deposite(); void withdrawal(); void transaction(account []); }; void account :: create() { static int acc=1231; accno=acc+n; cout<<"\n\tENTER THE CUSTOMER NAME : "; cin>>name; cout<<"\n\t ENTER THE AGE : "; cin>>age; cout<<"\n\t ENTER THE AMOUNT : "; cin>>amt; // if(amt<=500) // cout<<"\n\tAMOUNT IS NOT SUFFICIENT TO CREATE AN ACCOUNT..."; cout<<"\n\t YOUR ACCOUNT NUMBER : "<<accno<<endl; n++; } void accinfo(account cus[],int ch) { int no,flag=0; cout<<"\n\t\tENTER YOUR ACCOUNT NUMBER : "; cin>>no; for(int i=0;i<=n&&flag==0;i++) if(no==cus[i].accno) { flag=1; switch(ch) { case 2: cus[i].balenq(); break; case 3: cus[i].deposite(); break; case 4: cus[i].withdrawal(); break; case 5: cus[i].transaction(cus); break; default: cout<<"\n\t\tEND OF THE OPERATION"; exit(1); } } if(flag==0) cout<<"\n\t\tYOUR ACCOUNT DOES NOT EXIST..."<<endl; } void account :: balenq() { cout<<"\n\t\tCUSTOMER NAME : "<< name << endl; cout<<"\n\t\tBALANCE : "<< amt << endl; } void account :: deposite() { int damt; cout<<"\n\t\tCUSTOMER NAME : "<< name <<endl; cout<<"\n\t\tBALANCE : "<< amt <<endl; cout<<"\n\tENTER THE AMOUNT TO BE DEPOSITED : "; cin>>damt; amt+=damt; cout<<"\n\t\tYOUR CURRENT BALANCE : "<<amt<<endl; } void account :: withdrawal() { int wamt; cout<<"\n\t\tCUSTOMER NAME : "<< name; cout<<"\n\t\tBALANCE : "<< amt; cout<<"\n\tENTER THE AMOUNT TO BE WITHDRAWN : "; cin>>wamt; if(amt-wamt>=500) { amt-=wamt; cout<<"\n\t\tYOUR CURRENT BALANCE : "<<amt; } else cout<<"\n\tYOUR BALANCE IS TOO LOW FOR WITHDRAWAL..."<<endl; } void account :: transaction (account cus[]) { int no,tamt,flag=0; cout<<"\n\tENTER THE RECEIVER'S ACCOUNT NUMBER : "; cin>>no; cout<<"\n\t\t ENTER THE AMOUNT : "; cin>>tamt; for(int i=0;i<=n&&flag==0;i++) if(cus[i].accno==no) { flag=1; cus[i].amt+=tamt; amt-=tamt; cout<<"\n\t\tYOUR CURRENT BALANCE : "<<amt<<endl; cout<<"\n\t\t RECEIVER'S BALANCE : "<<cus[i].amt<<endl; } if(flag==0) cout<<"\n\tRECEIVER'S ACCOUNT NUMBER IS NOT AVALIABLE..."<<endl; } void main() { account cus[10]; int ch; do { cout<<"\n\t\t BANK ACCOUNT"; cout<<"\n\t\t ************\n"; cout<<"\n\t\t1.CREATE AN ACCOUNT"; cout<<"\n\t\t2.BALANCE ENQUIRY"; cout<<"\n\t\t3.DEPOSITE"; cout<<"\n\t\t4.WITHDRAWAL"; cout<<"\n\t\t5.TRANSACTION"; cout<<"\n\t\t6.EXIT\n\n"; cout<<"\n\t\tENTER YOUR CHOICE : "; cin>>ch; if(ch==1) cus[n].create(); else accinfo(cus,ch); }while(1); }
What is probability to guarantee that the task a programmer is going to create will be created and be able to run on a particular system (RTOS/GPOS).
Given that two int variables, total and amount , have been declared, write a sequence of statements that: initializes total to 0 reads three values into amount , one at a time. After each value is read in to amount , it is added to the value in total (that is, total is incremented by the value in amount ). Instructor's notes: If you use a loop, it must be a for loop. And if you use a loop control variable for counting, you must declare it.
what is meant by linking error? how can i solve it? if there is a linking error " unable to open file 'cos.obj'? then what should i do?
I can not get my C++ program to work right. It is supposed to tell if a word is a palindrome or not, but it only tells thet the word is not a palindrome. And I can't fix it.
how to convert decimal to binary in c using while loop without using array
50 Answers Apple, Aptech, Arwen Tech, BCS, C2D Software, CEC,
What are the different types of errors in C and when they occur?
How to create a program that lists countries capitals when country is entered? (Terribly sorry, I'm a complete novist to coding with C, am looking for inspiration and general tips on how to code and create this program.)
2. A student studying Information Technology at Polytechnic of Namibia is examined by coursework and written examination. Both components of assessment carry a maximum of 50 marks. The following rules are used by examiners in order to pass or fail students. a. A student must score a total of 40% or more in order to pass (total = coursework marks + examination marks) b. A total mark of 39% is moderated to 40% c. Each component must be passed with a minimum mark of 20/50. If a student scores a total of 40% or more but does not achieve the minimum mark in either component he/she is given a technical fail of 39% (this mark is not moderated to 40%) d. Grades are awarded on marks that fall into the following categories. Mark 100-70 69-60 59-50 49-40 39-0 Grade A B C D E Write a program to input the marks for both components (coursework marks out of 50 and examination marks out of 50), out put the final mark and grade after any moderation. [30]
C C++ Errors 
