void main()
{
for(int i=0;i<5;i++);
printf("%d",i);
}
What is the output?..
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Answers were Sorted based on User's Feedback
Answer / kumaran
declaring int i inside for loop is not available in
traditional 'c'
| Is This Answer Correct ? | 73 Yes | 22 No |
Answer / mahfooz
we can not declare loop condition variable in c..we can do
in c++.
| Is This Answer Correct ? | 35 Yes | 16 No |
Answer / samir isakoski
why shoul have a cout if is c++
buth this is c (printf)
and why cannot daclare a int in the for ciclus
| Is This Answer Correct ? | 17 Yes | 7 No |
Answer / divya
no output because the for loop is terminated with a semicolon which means the loop will terminate at once.
| Is This Answer Correct ? | 15 Yes | 9 No |
hi friend i am ricky dobriyal.
if this programe in c then this program produce error
expression syntex error.
if in c++ then it will produce o/p=5
| Is This Answer Correct ? | 9 Yes | 6 No |
Answer / pramod
if it is in C it displays an error "indicating that "i"
cannot be declared in loop and i as undefined symbol"
if it the case of C++ it displays "5" because C++ supports
dynamic declaration and once declared anywhere in the
program(even in loops) can be used anytime in that program
| Is This Answer Correct ? | 1 Yes | 1 No |
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void main() { for(int i=0;i<5;i++); printf("%d",i); } What is the output?..
31 Answers CTS, iGate, HCL, College School Exams Tests, SmartData,
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