void main()
{
for(int i=0;i<5;i++);
printf("%d",i);
}

What is the output?..




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void main() { for(int i=0;i<5;i++); printf("%d",i); } What is the output?....

Answer / kumaran

declaring int i inside for loop is not available in
traditional 'c'

Is This Answer Correct ?    72 Yes 22 No

void main() { for(int i=0;i<5;i++); printf("%d",i); } What is the output?....

Answer / mariaalex007

Answer is 5..........

Is This Answer Correct ?    102 Yes 71 No

void main() { for(int i=0;i<5;i++); printf("%d",i); } What is the output?....

Answer / mahfooz

we can not declare loop condition variable in c..we can do
in c++.

Is This Answer Correct ?    35 Yes 16 No




void main() { for(int i=0;i<5;i++); printf("%d",i); } What is the output?....

Answer / samir isakoski

why shoul have a cout if is c++

buth this is c (printf)

and why cannot daclare a int in the for ciclus

Is This Answer Correct ?    17 Yes 7 No

void main() { for(int i=0;i<5;i++); printf("%d",i); } What is the output?....

Answer / divya

no output because the for loop is terminated with a semicolon which means the loop will terminate at once.

Is This Answer Correct ?    15 Yes 9 No

void main() { for(int i=0;i<5;i++); printf("%d",i); } What is the output?....

Answer / ricky dobriyal

hi friend i am ricky dobriyal.
if this programe in c then this program produce error
expression syntex error.
if in c++ then it will produce o/p=5

Is This Answer Correct ?    9 Yes 6 No

void main() { for(int i=0;i<5;i++); printf("%d",i); } What is the output?....

Answer / radha raman

output=5

Is This Answer Correct ?    2 Yes 1 No

void main() { for(int i=0;i<5;i++); printf("%d",i); } What is the output?....

Answer / pramod

if it is in C it displays an error "indicating that "i"
cannot be declared in loop and i as undefined symbol"

if it the case of C++ it displays "5" because C++ supports
dynamic declaration and once declared anywhere in the
program(even in loops) can be used anytime in that program

Is This Answer Correct ?    1 Yes 1 No

void main() { for(int i=0;i<5;i++); printf("%d",i); } What is the output?....

Answer / avi

Error will occur

Is This Answer Correct ?    2 Yes 2 No

void main() { for(int i=0;i<5;i++); printf("%d",i); } What is the output?....

Answer / sansiri

the answer is...........0




because in c,c++ program when the semicolon is present then it is considered as one statement
here for loop has a semicolon so it consider one statement and execute only one so that the initial value o is printed

Is This Answer Correct ?    0 Yes 0 No

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