void main()
{
for(int i=0;i<5;i++);
printf("%d",i);
}
What is the output?..
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Answer / kumaran
declaring int i inside for loop is not available in
traditional 'c'
| Is This Answer Correct ? | 72 Yes | 22 No |
Answer / mahfooz
we can not declare loop condition variable in c..we can do
in c++.
| Is This Answer Correct ? | 35 Yes | 16 No |
Answer / samir isakoski
why shoul have a cout if is c++
buth this is c (printf)
and why cannot daclare a int in the for ciclus
| Is This Answer Correct ? | 17 Yes | 7 No |
Answer / divya
no output because the for loop is terminated with a semicolon which means the loop will terminate at once.
| Is This Answer Correct ? | 14 Yes | 9 No |
hi friend i am ricky dobriyal.
if this programe in c then this program produce error
expression syntex error.
if in c++ then it will produce o/p=5
| Is This Answer Correct ? | 9 Yes | 6 No |
Answer / pramod
if it is in C it displays an error "indicating that "i"
cannot be declared in loop and i as undefined symbol"
if it the case of C++ it displays "5" because C++ supports
dynamic declaration and once declared anywhere in the
program(even in loops) can be used anytime in that program
| Is This Answer Correct ? | 1 Yes | 1 No |
Answer / ramveer
for the first loop i is 0 so 0 is printed
for 2nd time i++ i becomes 1 so 1 is printed
for 3rd time i becomes 2 so 2 gets printed
for 4th time i becomes 3 so it gets prited
for 5th time i becomes 4 so it gets printed
now for this time i has became 5 and this isn't in loop boudary as the condition is i<5 so its breaks out of loop.
so the ans is "0 1 2 3 4" .
| Is This Answer Correct ? | 9 Yes | 9 No |
2. A student studying Information Technology at Polytechnic of Namibia is examined by coursework and written examination. Both components of assessment carry a maximum of 50 marks. The following rules are used by examiners in order to pass or fail students. a. A student must score a total of 40% or more in order to pass (total = coursework marks + examination marks) b. A total mark of 39% is moderated to 40% c. Each component must be passed with a minimum mark of 20/50. If a student scores a total of 40% or more but does not achieve the minimum mark in either component he/she is given a technical fail of 39% (this mark is not moderated to 40%) d. Grades are awarded on marks that fall into the following categories. Mark 100-70 69-60 59-50 49-40 39-0 Grade A B C D E Write a program to input the marks for both components (coursework marks out of 50 and examination marks out of 50), out put the final mark and grade after any moderation. [30]
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