Interested to Buy Any Domain ? << Click Here >> for more details...
void main()
{
for(int i=0;i<5;i++);
printf("%d",i);
}
What is the output?..
- 32 Answers
- 74021 Views
- College School Exams Tests, CTS, HCL, iGate, SmartData, I also Faced
- E-Mail Answers
Answers were Sorted based on User's Feedback
Answer / kumaran
declaring int i inside for loop is not available in
traditional 'c'
| Is This Answer Correct ? | 80 Yes | 30 No |
Answer / mahfooz
we can not declare loop condition variable in c..we can do
in c++.
| Is This Answer Correct ? | 38 Yes | 20 No |
Answer / samir isakoski
why shoul have a cout if is c++
buth this is c (printf)
and why cannot daclare a int in the for ciclus
| Is This Answer Correct ? | 17 Yes | 11 No |
Answer / divya
no output because the for loop is terminated with a semicolon which means the loop will terminate at once.
| Is This Answer Correct ? | 15 Yes | 12 No |
Answer / shilpi
it will give 6 as a answer because condition is true inside and then it will increase its value by 1 and the terminate from the loop.
| Is This Answer Correct ? | 2 Yes | 0 No |
hi friend i am ricky dobriyal.
if this programe in c then this program produce error
expression syntex error.
if in c++ then it will produce o/p=5
| Is This Answer Correct ? | 10 Yes | 9 No |
Answer / pramod
if it is in C it displays an error "indicating that "i"
cannot be declared in loop and i as undefined symbol"
if it the case of C++ it displays "5" because C++ supports
dynamic declaration and once declared anywhere in the
program(even in loops) can be used anytime in that program
| Is This Answer Correct ? | 2 Yes | 2 No |
Answer / marius
if i have
$x=(11,22,33,44,55);
for($i=0;$i<5;$i++)
echo$x[$i]." ";
and we will print this:
11 22 33 44 55
$i=0 => 11
$i<5 => 44
$i++ => 55
ghigamarius@gmail.com
| Is This Answer Correct ? | 1 Yes | 2 No |
Given an int variable n that has been initialized to a positive value and, in addition, int variables k and total that have already been declared, use a do...while loop to compute the sum of the cubes of the first n whole numbers, and store this value in total . Thus if n equals 4, your code should put 1*1*1 + 2*2*2 + 3*3*3 + 4*4*4 into total . Use no variables other than n , k , and total .
Display this kind of output on screen. 1 0 1 1 0 1 3. Display this kind of output on screen. 1 1 0 1 0 1 4. Display this kind of output on screen. 1 1 0 1 0 1 5.Display this kind of output on screen. 1 2 3 4 5 6 7 8 9 10
what is meant by linking error? how can i solve it? if there is a linking error " unable to open file 'cos.obj'? then what should i do?
which typw of errors ? & how to solve it ?
To generate the series 1+3+5+7+... using C program
#include<>stdio.h> #include<>conio.h> { printf("hello"); void main() getch(); } what the out put of this program and why ......plz clear my answer
what is run time error?
I'm having trouble with coming up with the correct code. Thank You!! The assignment was to write a program using string functions that accepts a price of an item and displays its coded value. The base of the keys: X C O M P U T E R S 0 1 2 3 4 5 6 7 8 9 Sample I/O Dialogue: Enter Price: 489.50 Coded Value: PRS.UX
printy(a=3,a=2)
#include<iostream.h> #include<stdlib.h> static int n=0; class account { int age,accno; float amt; char name[20]; public: friend void accinfo(account [] ,int); void create(); void balenq(); void deposite(); void withdrawal(); void transaction(account []); }; void account :: create() { static int acc=1231; accno=acc+n; cout<<"\n\tENTER THE CUSTOMER NAME : "; cin>>name; cout<<"\n\t ENTER THE AGE : "; cin>>age; cout<<"\n\t ENTER THE AMOUNT : "; cin>>amt; // if(amt<=500) // cout<<"\n\tAMOUNT IS NOT SUFFICIENT TO CREATE AN ACCOUNT..."; cout<<"\n\t YOUR ACCOUNT NUMBER : "<<accno<<endl; n++; } void accinfo(account cus[],int ch) { int no,flag=0; cout<<"\n\t\tENTER YOUR ACCOUNT NUMBER : "; cin>>no; for(int i=0;i<=n&&flag==0;i++) if(no==cus[i].accno) { flag=1; switch(ch) { case 2: cus[i].balenq(); break; case 3: cus[i].deposite(); break; case 4: cus[i].withdrawal(); break; case 5: cus[i].transaction(cus); break; default: cout<<"\n\t\tEND OF THE OPERATION"; exit(1); } } if(flag==0) cout<<"\n\t\tYOUR ACCOUNT DOES NOT EXIST..."<<endl; } void account :: balenq() { cout<<"\n\t\tCUSTOMER NAME : "<< name << endl; cout<<"\n\t\tBALANCE : "<< amt << endl; } void account :: deposite() { int damt; cout<<"\n\t\tCUSTOMER NAME : "<< name <<endl; cout<<"\n\t\tBALANCE : "<< amt <<endl; cout<<"\n\tENTER THE AMOUNT TO BE DEPOSITED : "; cin>>damt; amt+=damt; cout<<"\n\t\tYOUR CURRENT BALANCE : "<<amt<<endl; } void account :: withdrawal() { int wamt; cout<<"\n\t\tCUSTOMER NAME : "<< name; cout<<"\n\t\tBALANCE : "<< amt; cout<<"\n\tENTER THE AMOUNT TO BE WITHDRAWN : "; cin>>wamt; if(amt-wamt>=500) { amt-=wamt; cout<<"\n\t\tYOUR CURRENT BALANCE : "<<amt; } else cout<<"\n\tYOUR BALANCE IS TOO LOW FOR WITHDRAWAL..."<<endl; } void account :: transaction (account cus[]) { int no,tamt,flag=0; cout<<"\n\tENTER THE RECEIVER'S ACCOUNT NUMBER : "; cin>>no; cout<<"\n\t\t ENTER THE AMOUNT : "; cin>>tamt; for(int i=0;i<=n&&flag==0;i++) if(cus[i].accno==no) { flag=1; cus[i].amt+=tamt; amt-=tamt; cout<<"\n\t\tYOUR CURRENT BALANCE : "<<amt<<endl; cout<<"\n\t\t RECEIVER'S BALANCE : "<<cus[i].amt<<endl; } if(flag==0) cout<<"\n\tRECEIVER'S ACCOUNT NUMBER IS NOT AVALIABLE..."<<endl; } void main() { account cus[10]; int ch; do { cout<<"\n\t\t BANK ACCOUNT"; cout<<"\n\t\t ************\n"; cout<<"\n\t\t1.CREATE AN ACCOUNT"; cout<<"\n\t\t2.BALANCE ENQUIRY"; cout<<"\n\t\t3.DEPOSITE"; cout<<"\n\t\t4.WITHDRAWAL"; cout<<"\n\t\t5.TRANSACTION"; cout<<"\n\t\t6.EXIT\n\n"; cout<<"\n\t\tENTER YOUR CHOICE : "; cin>>ch; if(ch==1) cus[n].create(); else accinfo(cus,ch); }while(1); }
what is exceptions?
How to create a program that lists countries capitals when country is entered? (Terribly sorry, I'm a complete novist to coding with C, am looking for inspiration and general tips on how to code and create this program.)
C C++ Errors 
