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Given an int variable n that has already been declared and
initialized to a positive value, and another int variable
j that has already been declared, use a do...while loop to
print a single line consisting of n asterisks. Thus if n
contains 5, five asterisks will be printed. Use no variables
other than n and j .
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Answer / venkadesan
n is not get the values
so,it'a no either printed
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / mahfooz
//1st method..
there is no use of j.as explained below
int j,n=psitive value;
do
{
cout<<"*";
n--;
}while(n!=0);
//2nd we can use j..
int j=0;
do
{
cout<<"*";
j++;
}while(j!=n);
| Is This Answer Correct ? | 11 Yes | 14 No |
Given that two int variables, total and amount, have been declared, write a loop that reads integers into amount and adds all the non-negative values into total. The loop terminates when a value less than 0 is read into amount. Don't forget to initialize total to 0. Instructor's notes: This problem requires either a while or a do-while loop.
Assume that the int variables i and j have been declared, and that n has been declared and initialized. Write code that causes a "triangle" of asterisks of size n to be output to the screen. Specifically, n lines should be printed out, the first consisting of a single asterisk, the second consisting of two asterisks, the third consistings of three, etc. The last line should consist of n asterisks. Thus, for example, if n has value 3, the output of your code should be * ** *** You should not output any space characters. Hint: Use a for loop nested inside another for loop.
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