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void main()
{
int i=5;
printf("%d",i+++++i);
}
- 14 Answers
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Answer / nagarajan
If it is i++ + ++i the output will be 12 because
i++ =6
++1 =6
6+6=12
but in this case continuous five plus will show error .
compiler cannot identify operands there must be a space in between
| Is This Answer Correct ? | 55 Yes | 21 No |
Answer / junaid
well if you write all 5+ without space then it will give an error because compiler will not recognize it
you can write i++ + ++i or ++i + i++
answer in both statements will be 12
| Is This Answer Correct ? | 16 Yes | 7 No |
Answer / harshawardhan
all functions pass the value from right to left and printf()
is one function therefore
i++ + ++i
in this siquence first solve the ++i and then solve the i++
first incrment by one i.e. 6 and then it solve i++ i.e. 5
printf("%d",i++ + ++i);
printf("%d",i++ + 6);
printf("%d",6 + 6);
printf("%d",12);
And therefoe output is:-
12
| Is This Answer Correct ? | 13 Yes | 9 No |
Answer / gaurav tyagi
first of all
i want to say every one plz write ans if you are fully confident otherwise run it
///in this program a error is occurs because compiler not recognize the code <i am run this one>
| Is This Answer Correct ? | 3 Yes | 3 No |
Answer / srinivas
printf allways it will work from right to left so first
++i=6 after that i++ also 6 so 6+6=12 ..
| Is This Answer Correct ? | 9 Yes | 10 No |
Answer / vns
Increment operator(++i) only increases i value. At first ++i, i value becomes 6. Then there's another ++i, now i value is 7. both increment operations are evaluated since it has higher precedence than addition. So (++i) +(++i)= (i)+(i)= 7+7=14.
compile and run the program and you will get 14.
| Is This Answer Correct ? | 1 Yes | 2 No |
Answer / taruna
plzzz explain this ...why can't its answer be 12..???
plzz give proper explaination....waitin!!!
| Is This Answer Correct ? | 4 Yes | 7 No |
UINT i,j; i = j = 0; i = ( i++ > ++j ) ? i++ : i--; explain pls....
void main() { int i=5; printf("%d",i+++++i); }
void main() { int i=5,y=3,z=2,ans; clrscr(); printf("%d",++i + --z + i++ + --i * ++y); i=5,y=3,z=2; ans=++i + --z + i++ + --i * ++y; printf("\n%d",ans); getch(); } Its output is 37 and 31.... Please explain me why its different How it works.....
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