UINT i,j;
i = j = 0;
i = ( i++ > ++j ) ? i++ : i--;
explain pls....
- 5 Answers
- 14627 Views
- I also Faced
- E-Mail Answers
Answers were Sorted based on User's Feedback
Answer / raj
1.we know that i=j=0 initially
2.then it will checks the non-incremented 'i' value(i.e 0)
with incremented 'j' value(i.e 1). So obviously condition
is falls.
3.now false statement has to be executed i.e (i--),before
executing this 'i' value is (i.e incremented value)'1'
after executing false condition(i.e i--)the value of 'i'
becomes '0'.
4.So the value of 'i' is '0'.
| Is This Answer Correct ? | 30 Yes | 2 No |
Answer / vignesh1988i
UNIT i,j :
this line indicates that UNIT is an user defined data type. it may been declared as follows :
typedf int UNIT
we are making the code more readable
i=j=0 : indicates that the var. i and j are declared as 0
i=(i++>++j) ? i++ : i-- : the process here is
i++ is an post incrementation . if this is compared with any relational or any operaters first that value will be operated first and the 'i' will get incremented ........
but ++j if we take first thing it will increment the value and then operation will be performed
so when it is compared first i will be 0 and j will be 1 so 0 is not greater than 1. so false, so it will go to the statement after ':' so i-- is there so final value of i will be 0.
thank u
| Is This Answer Correct ? | 6 Yes | 1 No |
Answer / dhatchina moorthy
r u guys nuts the person answered first is right.he
non-incremented 'i' value(i.e 0)
with incremented 'j' value(i.e 1). So condition
is falls.
so false part has to be executed i.e (i--),before
executing this 'i' value is (i.e incremented value)'1'
after executing false condition(i.e i-- her it doesn't
increment bcoz it is postfix operator)the value of 'i'
becomes '1'.
still having doubts, compile this program in ur pc.
| Is This Answer Correct ? | 5 Yes | 1 No |
Answer / prem_mallappa
All answers are incorrect except this one.
Read c-faqs (Frequently asked questions about C)
The answer is unpredictable or implementation defined.
| Is This Answer Correct ? | 0 Yes | 1 No |
Answer / chaneswara reddy
(i++ > j++) gives 0 because 0 > 0 is false so it return 0.
before returning 0 i is 1 ,but it is overwrite by 0.
In the Conditional operator false means ,it executes i++;
so i is 1.
| Is This Answer Correct ? | 3 Yes | 19 No |
#include<>stdio.h> #include<>conio.h> { printf("hello"); void main() getch(); } what the out put of this program and why ......plz clear my answer
How to convert hexadecimal to binary using c language..
1 Answers Bajaj, GAIL, Satyam, Zenqa,
what is exceptions?
Write a program to accept two strings of Odd lengths. Then take all odd characters from one string and even characters from the other and concatenate and produce a string.
full c programming error question based problem
Answering Yes or No in C++...using only stdio.h and conio.h..........help me please...? here's must be the output of the program: Screen A Exam No. items Score 1 20 20 2 35 35 Another Entry? [Y] or [N] : Screen B: Record No. Student's Name: 1 Fernando Torres 2 Chuck Norris Note: if you press Y, the program must repeat the procedure in screen A, then if N, the program must proceed to the screen B....Please Help me out............
What is the out put of this programme? int a,b,c,d; printf("Enter Number!\n"); scanf("%d",&a); while(a=!0) { printf("Enter numbers/n"); scanf("%d%d%d",&b,&c,&d); a=a*b*c*d; } printf("thanks!"); getche(); Entering numbers are a=1,b=2,c=3,d=4 b=3,c=4,d=-5 b=3,c=4,d=0
what is the error in the following code: main() { int i=400,j; j=(i*i)/i; }
printy(a=3,a=2)
Assume that the int variables i and j have been declared, and that n has been declared and initialized. Write code that causes a "triangle" of asterisks of size n to be output to the screen. Specifically, n lines should be printed out, the first consisting of a single asterisk, the second consisting of two asterisks, the third consistings of three, etc. The last line should consist of n asterisks. Thus, for example, if n has value 3, the output of your code should be * ** *** You should not output any space characters. Hint: Use a for loop nested inside another for loop.
quoroum of computer languages?
void main() { int i=5; printf("%d",i+++++i); }
C C++ Errors 
