Answer / babitha

Precondition:let the prime no be n
case1: expected o/p (prime no)result
divide the no n by 1 remainder=0 pass
divide the no n by n remainder=0 pass

divide the no n by 2 remainder!=0 pass
.
.
divide the no n by upto n-1 and if remanider not equal zero
then it is a prime no.

Answer / guest

Testcase ID test condition Result
1 1 true
2 3 true
3 4 false
4 5 true

Answer / guest

-field area should take only numeric value
-number should not contain fraction or decimal
-number should not contain any special character
-number should be divisible by 1
-if number is divisible by other than 1 then reminder should
be 1

Answer / pavithramadhesh

import java.util.Scanner;

public class prime {
public static void main(String[] args) {
Scanner sc=new Scanner(System.in);
System.out.println("Enter a Number: ");
int a=sc.nextInt();
if(((a/a)==1) && ((a/1)==a)){
System.out.println(a+" is Prime Number");
}else {
System.out.println(a+" is Not Prime Number");
}
}
}

Answer / md.mosaj gohar

- chech if the number is not a decimal no.
- check if the number is not of the from p/q
- check if the number is not a negative no.
- if the number is a natural number a greater than 6 then,
-if it can be converted to the form 6k-1or
6k+1,then it is prime no.else not.
- for natural nos. less than 6: 2,3 7 5 are prime nos. to
be taken as granted.

Answer / surya gandepalli

for input = 1 , Ouput: should be "Not a Prime Number"

Prime Number(Definition): A number Greater Than 1 is called
a prime number, if it has exactly two factors, namely 1 and
the number itself.

so check with the boundary values.
({INPUT},OUTPUT ) = ({0,1,4}, {NOT PRIME})
({INPUT},OUTPUT ) = ({2,3,5}, {is PRIME})
{Destructive INPUT}=(Type Special Characters),(Copy Past
Special Characters from a Note Pad document Using Mouse ))

0 (Zero is the only Whole Number which is not a natural number)
1

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