Answer / sharma

If you want best 3, then we need 11 races as Alok Chandra
said.
But ideally we no need to arrang horses for races. Race any
5 horses in each race and select first 3. Repeat this 11
times, you will get best 3.
This is for the worst case.

Answer / ashutosh upadhyay

I calculated 8 races. Here is the logic

1. 5 races, R1 to R5 s.t. each race has 5 horses and every
horse appears in exactly one of R1 to R5. Discard 4th and
5th positioned horses. Note that 3rd positioned horses
cannot be discarded as 3rd horse of Ri may be faster than
toppers of other 4 races.

2. R6 between 1st ranked horses of races R1 to R5. Topmost
ranked horse is the fastest horse.

3. R7 between
- 2nd and 3rd toppers of R6
- 2nd position holders of those three races of R1 to
R5 whose topmost horses were ranked in top 3 in R6.
Winner of R7 is the 2nd fastest horse.

4. R8 between
- All horses except winner from R7
- 3rd position holder of the race out of R1 to R5 whose
topmost horse won R6.
Fastest horse will be 3rd fastest horse.

Answer / saravanan

6 races

Answer / ashish :|

k...if timing devices ver not yet invented :P


1st hold 5 prelim races.....

then


1.hold a race among all the 1st place horses[of the prelims]
(let it be race x)......this will determine the fastest horse..

2.hold a race among all the 2nd place horses[of the prelims]
(let it be race y)......

3.hold a race among all the 3rd place horses[of the prelims]
(let it be race z)........

4.then hold a race among the 2nd & 3rd placed horses of race
x,1st & 2nd of race y and 1st place of race z..........this
will determine the 2nd&3rd fastest horses.....

.
. . 5+4=9..........9



v need a min of 9 races 2 determine the top 3
horses(according 2 me)

Answer / anjali

MINIMUM 6 RACES REQUIRED

conduct 5 races, in each race 5 horeses

out of 5 races to select 1 horse from each race (total 5
horses selected)

conduct 6 race with selected 5 horeses
out of that select top 3 horses

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